Magnetism
41 Torque on a Current Loop: Motors and Meters
Learning Objectives
- Describe how electric motors and analog meters operate using the torque produced on a current-carrying loop.
- Calculate the torque acting on a current-carrying loop placed in a magnetic field.
Electric motors are among the most common applications of magnetic forces. They power devices ranging from electric toothbrushes and infusion pumps to MRI patient tables, ventilators, laboratory centrifuges, and surgical tools. In every electric motor, a current-carrying loop of wire is placed in a magnetic field. The interaction between the current and the magnetic field produces a torque, causing the loop to rotate and converting electrical energy into mechanical work (Figure 41.1).

To understand how a motor works, we examine the magnetic forces acting on each segment of the rectangular loop shown in Figure 41.1. The magnetic field is assumed to be uniform across the loop, which has width [latex]w[/latex] and height [latex]l[/latex].
The forces acting on the top and bottom segments of the loop are directed vertically, parallel to the axis of rotation. Because these forces act along the axis, they do not produce torque. Furthermore, they are equal in magnitude and opposite in direction, so they cancel and produce no net force on the loop.
The situation is different for the two vertical sides of the loop. As illustrated in Figure 41.2(a), the magnetic forces on these sides are also equal in magnitude and opposite in direction. Although the net force remains zero, each force acts at a distance from the axis of rotation, producing a torque. Since both torques act in the same rotational direction, they add together.
Torque is defined by
where [latex]F[/latex] is the applied force, [latex]r[/latex] is the distance from the axis of rotation to the point where the force acts, and [latex]\theta[/latex] is the angle between the position vector and the force.
For each side of the loop, the distance from the axis is [latex]r=w/2[/latex]. Adding the torques from both sides gives

Each vertical segment has length [latex]l[/latex] and is perpendicular to the magnetic field, so the magnetic force on each side is
Substituting this expression into the torque equation gives
Most practical motors contain many loops of wire rather than just one. If the coil has [latex]N[/latex] turns, the total torque is multiplied by [latex]N[/latex]. Since the area enclosed by each loop is
the torque on a current-carrying loop becomes
This equation applies to loops of any shape placed in a uniform magnetic field. Here, [latex]N[/latex] is the number of turns, [latex]I[/latex] is the current, [latex]A[/latex] is the area of each loop, [latex]B[/latex] is the magnetic field strength, and [latex]\theta[/latex] is the angle between the magnetic field and a line perpendicular to the plane of the loop.
A useful feature of this arrangement is that the magnetic forces on opposite sides of the loop always cancel, producing no net force. Instead of causing the loop to translate, the magnetic field produces only a torque, allowing the loop to rotate smoothly.
Magnetic Torque in Healthcare
The same physical principle is used in many medical technologies. Small electric motors power syringe pumps, ventilators, robotic surgical instruments, and dental tools. Precision analog meters, discussed later in this section, also rely on magnetic torque to rotate a pointer by an amount proportional to the electrical current being measured. Although modern digital displays have largely replaced analog meters, the underlying physics remains important for understanding many biomedical instruments.
Example 41.1: Calculating the Torque on a Current-Carrying Loop
A square coil with 100 turns has sides that are 10.0 cm long. The coil carries a current of 15.0 A and is placed in a uniform magnetic field of 2.00 T. Calculate the maximum torque acting on the coil.
Strategy
Use the torque equation
The maximum torque occurs when [latex]\theta=90^\circ[/latex], so [latex]\sin\theta=1[/latex]. First calculate the area of the square loop.
Solution
The area of the loop is
Substitute the known values into the torque equation:
Answer:
Discussion
This example illustrates how a relatively small coil can produce a substantial torque when it carries a current in a strong magnetic field. Increasing the current, magnetic field strength, number of turns, or loop area all increases the torque, making these quantities important design considerations in electric motors.
The torque calculated in the previous example is the maximum possible torque. As the loop rotates, the angle [latex]\theta[/latex] changes, causing the torque to decrease. When the plane of the loop becomes perpendicular to the magnetic field, [latex]\theta=0^\circ[/latex], the torque becomes zero. If the current remained unchanged, the torque would reverse direction after the loop passed this position, causing the coil to slow down and simply oscillate back and forth instead of continuing to rotate.
To produce continuous rotation, electric motors automatically reverse the direction of the current every half turn using a device called a commutator and stationary electrical contacts called brushes. Reversing the current reverses the magnetic forces on the coil, keeping the torque in the same rotational direction throughout the motion.

The same physical principle is used in many analog measuring instruments, including galvanometers, analog ammeters, voltmeters, and some automobile gauges. As shown in Figure 41.4, these devices resemble small electric motors, but instead of rotating continuously, the coil turns only through a limited angle.
The magnets are specially shaped so that the magnetic field remains nearly perpendicular to the current-carrying coil over its operating range. As a result, the magnetic torque depends primarily on the current rather than on the coil's orientation. A small spring provides an opposing torque, and the pointer comes to rest when the spring torque balances the magnetic torque. Because the magnetic torque is proportional to the current, the pointer deflection is also proportional to the current, producing a linear measurement scale. Increasing the loop area, magnetic field strength, or number of turns improves the instrument's sensitivity, allowing it to detect very small currents.

Section Summary
- The torque on a current-carrying loop in a uniform magnetic field is given by
[latex]\tau =NIAB\sin\theta,[/latex]
where [latex]N[/latex] is the number of turns, [latex]I[/latex] is the current, [latex]A[/latex] is the area of the loop, [latex]B[/latex] is the magnetic field strength, and [latex]\theta[/latex] is the angle between the magnetic field and the line perpendicular to the plane of the loop.
- The torque is maximum when [latex]\theta=90^\circ[/latex] and zero when [latex]\theta=0^\circ[/latex].
- Electric motors use a split-ring commutator and brushes to reverse the current every half revolution, allowing the torque to remain in the same rotational direction and produce continuous rotation.
- Analog meters, such as galvanometers, ammeters, and voltmeters, operate using the same principle. The magnetic torque is balanced by a spring, causing the pointer deflection to be proportional to the current.
Conceptual Questions
- Draw a diagram and use Right-Hand Rule 1 (RHR-1) to show that the magnetic forces acting on the top and bottom segments of the current loop in Figure 41.1 are parallel to the axis of rotation and therefore produce no torque.
Problems & Exercises
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- By what percentage is the torque produced by an electric motor reduced if its permanent magnets lose 5.0% of their magnetic field strength?
- By what percentage would the current need to increase to restore the original torque?
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- What is the maximum torque on a 150-turn square loop of wire, 18.0 cm on each side, carrying a current of 50.0 A in a 1.60-T magnetic field?
- What is the torque when [latex]\theta=10.9^\circ[/latex]?
- Find the current required to produce a maximum torque of [latex]9.00\ \text{N}\cdot\text{m}[/latex]. The loop has 50 square turns that are 15.0 cm on each side and is placed in a uniform 0.800-T magnetic field.
- Calculate the magnetic field strength required for a 200-turn square loop, 20.0 cm on each side, to produce a maximum torque of [latex]300\ \text{N}\cdot\text{m}[/latex] while carrying a current of 25.0 A.
- Verify that the SI units of torque, [latex]\text{N}\cdot\text{m}[/latex], are equivalent to the units obtained from the expression [latex]\text{A}\cdot\text{m}^2\cdot\text{T}[/latex].
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- At what angle [latex]\theta[/latex] is the torque on a current loop equal to 90.0% of its maximum value?
- At what angle is the torque equal to 50.0% of its maximum value?
- At what angle is the torque equal to 10.0% of its maximum value?
- A proton has a magnetic moment associated with its spin that can be modeled as a circular current loop of radius [latex]0.650\times10^{-15}\ \text{m}[/latex] carrying a current of [latex]1.05\times10^{4}\ \text{A}[/latex]. Determine the maximum torque on the proton in a 2.50-T magnetic field.
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- A 200-turn circular loop of radius 50.0 cm is mounted vertically with its axis oriented east-west. A current of 100 A flows clockwise when viewed from the east. At this location, the Earth's magnetic field has a strength of [latex]3.00\times10^{-5}\ \text{T}[/latex] and points due north, parallel to the ground. Determine the magnitude and direction of the torque on the loop.
- Would this arrangement be practical as an electric motor? Explain.
- Repeat Problem 48, but now place the loop flat on the ground with its current circulating counterclockwise when viewed from above. Assume the Earth's magnetic field has a magnitude of [latex]6.00\times10^{-5}\ \text{T}[/latex] and points due north at an angle of [latex]45.0^\circ[/latex] below the horizontal.
Glossary
- motor
- A device that converts electrical energy into mechanical energy by using the torque produced on a current-carrying loop in a magnetic field.
- meter
- An instrument that measures electrical quantities by balancing the magnetic torque on a current-carrying coil against a restoring spring, producing a pointer deflection proportional to the current.
- torque on a current loop
- The turning effect produced when a current-carrying loop is placed in a magnetic field, given by [latex]\tau = NIAB\sin\theta[/latex].
- commutator
- A split-ring electrical switch that reverses the direction of current in a rotating coil every half revolution, allowing a DC motor to continue rotating in the same direction.
- brushes
- Stationary electrical contacts that transfer current between the external circuit and the rotating commutator of a motor.
- galvanometer
- A sensitive analog instrument that measures small electric currents using the torque on a current-carrying coil in a magnetic field.
A device that converts electrical energy into mechanical energy by using the torque produced on a current-carrying loop in a magnetic field.
An instrument that measures electrical quantities by balancing the magnetic torque on a current-carrying coil against a restoring spring, producing a pointer deflection proportional to the current.
The turning effect produced when a current-carrying loop is placed in a magnetic field, given by [latex]\tau = NIAB\sin\theta[/latex].
A split-ring electrical switch that reverses the direction of current in a rotating coil every half revolution, allowing a DC motor to continue rotating in the same direction.
Stationary electrical contacts that transfer current between the external circuit and the rotating commutator of a motor.
A sensitive analog instrument that measures small electric currents using the torque on a current-carrying coil in a magnetic field.