Introduction to Quantum Physics
97 The Photoelectric Effect
Learning Objectives
- Describe a typical photoelectric-effect experiment.
- Determine the maximum kinetic energy of photoelectrons ejected by photons of one energy or wavelength when given the maximum kinetic energy of photoelectrons for a different photon energy or wavelength.
The Photoelectric Effect
One of the experiments that fundamentally changed our understanding of light is the photoelectric effect. When light shines on certain materials, it can eject electrons from their surface. This phenomenon demonstrated that light behaves not only as a wave but also as a collection of discrete packets of energy called photons, providing some of the strongest early evidence for quantum mechanics. The photoelectric effect is widely used in modern technology. Light sensors in cameras, automatic doors, smoke detectors, and photovoltaic (solar) cells all rely on the ability of light to release or move electrons within a material. Similar principles are also used in scientific instruments and medical imaging equipment.
The experiment shown in Figure 97.1 has been used for more than a century to investigate the interaction between light and matter. The apparatus consists of an evacuated tube containing a metal plate and a collector electrode connected to a variable voltage source. When electromagnetic radiation strikes the metal plate, electrons may be emitted from its surface. These emitted electrons, called photoelectrons, travel toward the collector, producing an electric current that can be measured. The voltage between the plate and the collector can be adjusted to oppose the motion of the emitted electrons. As the retarding voltage becomes more negative, fewer electrons have enough kinetic energy to reach the collector. The voltage required to stop even the fastest electrons provides a direct measurement of their maximum kinetic energy. For example, if a retarding potential of −3.00 V is just sufficient to stop the electrons, their maximum kinetic energy is 3.00 eV. The number of emitted electrons can also be measured by recording the current flowing through the circuit. Increasing the brightness (intensity) of the light generally increases the number of emitted electrons, making this type of device useful as a light detector or light meter.
Healthcare Connection
The true importance of the photoelectric effect lies not in the experiment itself, but in the conclusions that Albert Einstein drew from it in 1905. Classical wave theory predicted that increasing the intensity of light should eventually provide enough energy to eject electrons from any material. Experimental observations, however, contradicted this prediction. Einstein proposed that electromagnetic radiation is itself quantized. Instead of being a continuous flow of energy, light consists of individual particles, or photons, each carrying a specific amount of energy that depends only on the light's frequency.
where E is the energy of a photon, f is its frequency, and h is Planck's constant. This idea resembles Planck's explanation of blackbody radiation, but it goes one step further. Planck proposed that matter exchanges energy in discrete amounts. Einstein proposed that the electromagnetic radiation itself is quantized. In other words, light is composed of individual photons rather than being an entirely continuous wave. Each photon carries an energy equal to hf. When a photon interacts with an electron, the electron absorbs the photon's entire energy in a single event. Because ordinary light sources emit enormous numbers of photons every second, we normally perceive light as a continuous beam rather than as individual particles. In the next section, we will examine photons in greater detail and explore how their energies vary across the electromagnetic spectrum. First, however, we will use Einstein's photon model to explain the remarkable observations of the photoelectric effect.
The photoelectric effect exhibits several remarkable properties that cannot be explained by treating light as a purely classical electromagnetic wave. Instead, they are naturally explained if light consists of individual photons that interact one at a time with individual electrons. For simplicity, we will consider monochromatic light, in which every photon has the same energy, [latex]E=hf[/latex].
- There is a threshold frequency. Every material has a minimum frequency, called the threshold frequency ([latex]f_0[/latex]), below which no electrons are emitted, regardless of how intense the light is. If the energy of an individual photon is too small to overcome the attraction holding an electron within the material, the electron cannot escape. Classical wave theory predicts that increasing the light intensity should eventually provide enough energy, but experiments show that this never happens.
- Electrons are emitted without delay. As soon as a photon with sufficient energy strikes the material, an electron is ejected almost instantaneously. There is no measurable waiting time while energy accumulates. This immediate response is exactly what we expect if a single photon transfers all of its energy directly to a single electron.
- The number of emitted electrons depends on light intensity. Increasing the intensity of monochromatic light increases the number of photons striking the surface each second. Consequently, more electrons are emitted per unit time. However, the energy of each emitted electron remains unchanged because each electron still absorbs only one photon.
- The maximum kinetic energy depends only on the photon energy. Increasing the light intensity does not increase the maximum kinetic energy of the emitted electrons. Instead, it simply increases the number of emitted electrons. The kinetic energy depends only on the energy of the individual photons, which is determined by the light's frequency.
- Einstein's photoelectric equation. When a photon is absorbed by an electron, part of the photon's energy is required to free the electron from the material. The remaining energy becomes the electron's kinetic energy.
[latex]K_{\mathrm{max}}=hf-\mathrm{BE},[/latex]
where [latex]K_{\mathrm{max}}[/latex] is the maximum kinetic energy of the emitted electron, [latex]hf[/latex] is the energy of the incident photon, and [latex]\mathrm{BE}[/latex] is the binding energy, also known as the work function, of the material. The binding energy is related to the threshold frequency by
[latex]\mathrm{BE}=hf_0.[/latex]If the photon energy is less than the binding energy, no electrons are emitted. If the photon energy exceeds the binding energy, the excess energy appears as kinetic energy of the emitted photoelectron. Figure 97.3 illustrates this relationship graphically.
Einstein's explanation of the photoelectric effect marked one of the major turning points in modern physics. By proposing that electromagnetic radiation is composed of discrete particles called photons, he successfully explained experimental observations that classical wave theory could not. His model showed that each photon interacts with a single electron, transferring all of its energy in one event. Although Einstein introduced the photon concept to explain the photoelectric effect, the idea applies to all electromagnetic radiation. Radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays can all be described as streams of photons. The energy of each photon depends only on its frequency, while the intensity of the radiation depends on the number of photons arriving each second. In the next section, we will see that many properties of electromagnetic radiation can only be understood from the photon perspective. For example, the biological effects of ultraviolet radiation and the penetrating power of X-rays depend on the energy carried by individual photons rather than simply on the total intensity of the radiation.
Healthcare Connection
Einstein proposed the photon model in 1905, the same year he published his groundbreaking work on special relativity. Although he is most widely recognized for relativity, it was his explanation of the photoelectric effect that earned him the 1921 Nobel Prize in Physics. His work laid one of the foundations of quantum mechanics and transformed our understanding of the interaction between light and matter.
Example 97.1: Calculating Photon Energy and the Photoelectric Effect for Violet Light
Problem
- What is the energy, in both joules and electron volts, of a photon with a wavelength of 420 nm (violet light)?
- Calcium has a work function (binding energy) of 2.71 eV. What is the maximum kinetic energy of the electrons ejected when calcium is illuminated with 420-nm light?
Strategy
For part (a), use the photon-energy equation
Because the wavelength is given instead of the frequency, first use the relationship between wavelength and frequency to rewrite the equation in terms of wavelength. Then convert the result from joules to electron volts. For part (b), apply Einstein's photoelectric equation using the photon energy calculated in part (a).
Solution
- Photon energy: Since the wavelength is known, first determine the frequency from
[latex]c=f\lambda,[/latex]
which gives
[latex]f=\frac{c}{\lambda}.[/latex]Substituting this expression into the photon-energy equation produces a useful relationship:
[latex]E=\frac{hc}{\lambda}.[/latex]Now substitute the numerical values:
[latex]E=\frac{\left(6.63\times10^{-34}\,\mathrm{J\cdot s}\right)\left(3.00\times10^8\,\mathrm{m/s}\right)} {420\times10^{-9}\,\mathrm{m}} =4.74\times10^{-19}\,\mathrm{J}.[/latex]Convert the result to electron volts:
[latex]E=\left(4.74\times10^{-19}\,\mathrm{J}\right) \left(\frac{1\,\mathrm{eV}}{1.60\times10^{-19}\,\mathrm{J}}\right) =2.96\,\mathrm{eV}.[/latex] - Maximum kinetic energy of the emitted electrons: Apply Einstein's photoelectric equation:
[latex]K_{\mathrm{max}} =hf-\mathrm{BE} =2.96\,\mathrm{eV}-2.71\,\mathrm{eV} =0.246\,\mathrm{eV}.[/latex]
Discussion
The energy of an individual 420-nm photon is extremely small when expressed in joules, making it impossible for humans to detect single photons directly. However, expressing the energy in electron volts reveals that it is comparable to the energies involved in atoms and molecules. This is why photons can initiate chemical reactions, excite atoms, or eject electrons from materials. In this example, the photon has just enough energy to overcome calcium's work function, leaving only 0.246 eV as kinetic energy for the emitted photoelectron. If the wavelength were any longer (and therefore the photon energy lower), the photon would no longer have sufficient energy to eject an electron. You can verify that calcium's threshold wavelength is approximately 459 nm, corresponding to blue light. Light with longer wavelengths, such as green, yellow, or red light, does not have enough energy to produce the photoelectric effect in calcium. This threshold behavior is one of the strongest pieces of evidence that light transfers energy in discrete photons rather than as a continuous wave.
Interactive Exploration: The Photoelectric Effect
The photoelectric effect provided some of the earliest and strongest evidence that light exhibits both wave-like and particle-like behavior. In this interactive simulation, you will recreate the classic experiment that led Albert Einstein to propose that light consists of discrete packets of energy called photons. Investigate how changing the wavelength (or frequency) and intensity of the incident light affects the emission of electrons from a metal surface. Experiment with different metals, each having a different work function, and use the stopping voltage to determine the maximum kinetic energy of the emitted photoelectrons. Compare your observations with the predictions of classical wave theory and the photon model of light.
Guided Exploration
As you explore the simulation, answer the following questions.
- Illuminate the metal with low-frequency light. Are any electrons emitted? What happens if you increase only the light intensity while keeping the frequency constant?
- Increase the frequency of the light while keeping the intensity fixed. At what point do electrons begin to be emitted?
- Once photoelectrons are being emitted, increase the light intensity. How does the number of emitted electrons change? What happens to their maximum kinetic energy?
- Select different target metals. How does the threshold frequency depend on the material?
- Adjust the stopping voltage until the emitted electrons just fail to reach the collector. What physical quantity does this stopping voltage measure?
- Based on your observations, explain why the photoelectric effect cannot be explained using only the classical wave model of light.
Reflection. Compare your observations with Einstein's photon model. Notice that electrons are emitted only when the light frequency exceeds a threshold value determined by the material's work function. Increasing the intensity increases the number of emitted electrons but does not increase their maximum kinetic energy. These experimental observations provided convincing evidence that light transfers energy in discrete photons and played a central role in the development of quantum mechanics.
Section Summary
- The photoelectric effect is the emission of electrons from a material after it absorbs electromagnetic radiation.
- Einstein proposed that electromagnetic radiation is composed of discrete particles called photons, each having an energy given by
- The energy of a photon depends only on its frequency. Increasing the light intensity increases the number of photons, not the energy carried by each photon.
- The photoelectric effect is explained by individual photons transferring their energy to individual electrons.
- Every material has a characteristic work function (binding energy) that must be overcome before electrons can escape from its surface.
- The maximum kinetic energy of emitted photoelectrons is described by Einstein's photoelectric equation:
- The existence of a threshold frequency, the immediate emission of electrons, and the independence of photoelectron energy from light intensity all support the photon model of light.
Conceptual Questions
- Is visible light the only type of electromagnetic radiation that can cause the photoelectric effect?
- Which aspects of the photoelectric effect cannot be explained without photons? Which can be explained without photons? Are the latter inconsistent with the existence of photons?
- Is the photoelectric effect a direct consequence of the wave character of electromagnetic radiation or of the particle character of electromagnetic radiation? Explain briefly.
- Insulators (nonmetals) have a higher binding energy (BE) than metals, making it more difficult for photons to eject electrons from them. Discuss how this relates to the free charges in metals that make them good electrical conductors.
- If you pick up and shake a piece of metal that contains electrons free to move as an electric current, no electrons fall out. Yet if you heat the metal sufficiently, electrons can be emitted from its surface. Explain both observations in terms of how energy is supplied and distributed by shaking versus heating.
Problems & Exercises
- What is the longest-wavelength electromagnetic radiation that can eject a photoelectron from silver, given that its binding energy is 4.73 eV? Is this wavelength in the visible range?
- Find the longest-wavelength photon that can eject an electron from potassium, given that the binding energy is 2.24 eV. Is this visible electromagnetic radiation?
- What is the binding energy, in electron volts, of electrons in magnesium if the longest-wavelength photon capable of ejecting electrons has a wavelength of 337 nm?
- Calculate the binding energy, in electron volts, of electrons in aluminum if the longest wavelength capable of ejecting them is 304 nm.
- What is the maximum kinetic energy, in electron volts, of electrons ejected from sodium metal by 450-nm electromagnetic radiation, given that the binding energy is 2.28 eV?
- Ultraviolet radiation with a wavelength of 120 nm falls on gold metal, whose electrons have a binding energy of 4.82 eV. What is the maximum kinetic energy of the emitted photoelectrons?
- Violet light with a wavelength of 400 nm ejects electrons from sodium metal with a maximum kinetic energy of 0.860 eV. What is the binding energy of electrons in sodium?
- Ultraviolet radiation with a wavelength of 300 nm falls on uranium metal, ejecting electrons with a kinetic energy of 0.500 eV. What is the binding energy of electrons in uranium?
- What is the wavelength of electromagnetic radiation that ejects 2.00-eV electrons from calcium metal, given that its binding energy is 2.71 eV? What region of the electromagnetic spectrum does this wavelength belong to?
- Find the wavelength of photons that eject 0.100-eV electrons from potassium, given that the binding energy is 2.24 eV. Are these photons visible?
- What is the maximum speed of electrons ejected from a material by 80-nm photons if the electrons are bound to the material by 4.73 eV?
- Photoelectrons are ejected from a material with a binding energy of 2.71 eV by 420-nm photons. Once emitted, how long does it take these electrons to travel 2.50 cm to a detector?
- A laser with a power output of 2.00 mW and a wavelength of 400 nm is directed onto calcium metal.
- How many electrons are ejected each second?
- What power is carried away by the emitted electrons if the binding energy is 2.71 eV?
-
- Calculate the number of photoelectrons emitted each second from a 1.00-mm2 area of sodium metal illuminated by 500-nm electromagnetic radiation with an intensity of [latex]1.30~\text{kW/m}^2[/latex] (approximately the intensity of sunlight above Earth's atmosphere).
- Given that the binding energy is 2.28 eV, what power is carried away by the emitted electrons?
- The electrons carry away less power than is delivered by the incident photons. Where does the remaining energy go, and how could it be recovered?
- Unreasonable Results.
- Red light with a wavelength of 700 nm is incident on magnesium metal, whose electrons have a binding energy of 3.68 eV. Use [latex]K_{\mathrm{max}}=hf-\mathrm{BE}[/latex] to calculate the kinetic energy of the emitted electrons.
- What is unreasonable about the result?
- Which assumptions are unreasonable or inconsistent?
- Unreasonable Results.
- What is the binding energy of electrons in a material that emits 4.00-eV electrons when illuminated with 400-nm electromagnetic radiation?
- What is unreasonable about the result?
- Which assumptions are unreasonable or inconsistent?
Glossary
- photoelectric effect
- The phenomenon in which electrons are emitted from a material after it absorbs electromagnetic radiation.
- photon
- A quantum, or discrete particle, of electromagnetic radiation.
- photon energy
- The energy carried by a photon, given by
[latex]E=hf.[/latex]
- binding energy (work function)
- The minimum energy required to remove an electron from the surface of a material.
The phenomenon in which electrons are emitted from a material after it absorbs electromagnetic radiation.
A quantum, or discrete particle, of electromagnetic radiation.
The energy carried by a photon, given by
[latex]E=hf.[/latex]
The minimum energy required to remove an electron from the surface of a material.