Magnetism
39 The Hall Effect
Learning Objectives
- Describe the Hall effect and explain how it is produced.
- Calculate the Hall electromotive force (Hall emf) across a current-carrying conductor.
In the previous sections, we learned that magnetic fields exert forces on moving electric charges. We now examine what happens when those moving charges are confined within a conductor, such as a metal wire or a biological fluid like blood. The interaction between the moving charges and the magnetic field causes the charges to separate, producing a measurable voltage across the conductor. This phenomenon is known as the Hall effect and has become an important tool in science, engineering, and medicine.
Figure 39.1 illustrates how the Hall effect occurs. The magnetic field is perpendicular to both the motion of the charge carriers and the width of the conductor. In Figure 39.1(a), the current is carried by electrons, which drift to the left while the conventional current points to the right. The magnetic force pushes the electrons toward one side of the conductor, causing negative charge to accumulate there and leaving the opposite side relatively positive. This separation of charge creates a voltage across the conductor called the Hall emf, denoted by [latex]\epsilon[/latex].

The Hall effect provides a simple way to determine whether electric current is carried by positive or negative charges. As shown in Figure 39.1, the polarity of the Hall voltage reverses depending on the sign of the moving charge carriers. Historically, this experiment demonstrated that electrical current in metals is carried by electrons. In contrast, some semiconductors conduct electricity primarily through positive charge carriers (called holes), which produce the opposite Hall voltage. Today, the Hall effect remains an essential research tool for measuring charge density, carrier mobility, and other electronic properties of materials. At extremely low temperatures and under very strong magnetic fields, it also exhibits remarkable quantum behavior known as the quantum Hall effect.
The Hall effect also has numerous practical applications. Hall sensors are widely used to measure magnetic field strength, determine the position or speed of moving objects, and detect electrical current without direct contact. In healthcare, Hall-effect sensors can also be used to measure the flow of electrically conducting fluids, including blood. To understand these applications quantitatively, we first derive an expression for the Hall emf.
Consider the situation shown in Figure 39.2, where the magnetic field [latex]B[/latex], the charge velocity [latex]v[/latex], and the conductor width [latex]l[/latex] are mutually perpendicular. As the moving charges experience a magnetic force, they accumulate on one side of the conductor. This separation of charge creates an electric field that opposes further charge separation. Very quickly, the electric force balances the magnetic force, establishing equilibrium.
Canceling the charge [latex]q[/latex] gives
Because the magnetic field is uniform, the resulting electric field inside the conductor is also uniform. The relationship between electric field and voltage is
where [latex]l[/latex] is the width of the conductor. Substituting this expression into the previous equation gives
Solving for the Hall emf yields
where [latex]\epsilon[/latex] is the Hall voltage across a conductor of width [latex]l[/latex] through which charges move with speed [latex]v[/latex].

One of the most common applications of the Hall effect is the measurement of magnetic field strength using compact electronic devices called Hall probes. Because Hall probes can be made extremely small and accurately calibrated, they are widely used to map magnetic fields in scientific instruments, industrial equipment, and medical imaging systems.
Another important biomedical application is the measurement of blood flow. Blood contains electrically charged ions that move with the flowing fluid. As illustrated in Figure 39.3, when a magnetic field is applied perpendicular to the direction of blood flow, a Hall voltage develops across the blood vessel. The polarity of the voltage depends only on the directions of the magnetic field and the flow, while its magnitude is given by
where [latex]l[/latex] is the vessel diameter. By measuring the Hall voltage and knowing the magnetic field strength and vessel diameter, clinicians can determine the average blood flow velocity. This principle forms the basis of electromagnetic flowmeters, which have been used to measure blood flow during cardiovascular research and surgical procedures.

Example 39.1: Calculating the Hall emf in Blood Flow
A Hall-effect flow probe is placed around an artery, applying a magnetic field of [latex]0.100\;\text{T}[/latex] across the blood vessel, as shown in Figure 39.3. If the artery has an inside diameter of [latex]4.00\;\text{mm}[/latex] and the average blood flow speed is [latex]20.0\;\text{cm/s}[/latex], what Hall voltage is produced across the vessel?
Strategy
Because the magnetic field, blood flow velocity, and vessel diameter are mutually perpendicular, we can use the Hall effect equation
First convert all quantities to SI units before substituting into the equation.
Solution
Convert the given values:
- [latex]B = 0.100\;\text{T}[/latex]
- [latex]l = 4.00\;\text{mm}=4.00\times10^{-3}\;\text{m}[/latex]
- [latex]v = 20.0\;\text{cm/s}=0.200\;\text{m/s}[/latex]
Substitute into the Hall emf equation:
Expressing the result in microvolts,
Discussion
The Hall voltage generated by blood flow is extremely small—only about [latex]80\;\mu\text{V}[/latex]. In a real artery, this voltage changes continuously because blood flow is pulsatile rather than constant. Measuring such a small signal is also challenging because the electrical activity of the heart (recorded in an electrocardiogram, or ECG) produces voltages on the order of millivolts, which are much larger than the Hall voltage.
To isolate the desired signal, many electromagnetic blood-flow meters apply an alternating (AC) magnetic field instead of a constant one. The resulting Hall voltage oscillates at the same known frequency, allowing electronic filters and amplifiers to selectively detect the blood-flow signal while rejecting background electrical noise, including the ECG. This technique enables accurate, non-invasive measurements of blood flow in cardiovascular research and some clinical applications.
Section Summary
- The Hall effect is the production of a voltage, called the Hall emf ([latex]\epsilon[/latex]), across a current-carrying conductor when it is placed in a magnetic field.
- When the magnetic field, charge velocity, and conductor width are mutually perpendicular, the Hall emf is given by
[latex]\epsilon = Blv[/latex]
where [latex]B[/latex] is the magnetic field strength, [latex]l[/latex] is the width of the conductor, and [latex]v[/latex] is the drift velocity of the charge carriers.
- The Hall effect can be used to determine the sign of the charge carriers, measure magnetic field strength, and measure the flow rate of electrically conductive fluids such as blood.
Conceptual Questions
- Explain how the Hall effect could be used to determine the density of free charge carriers in a conductor. Hint: Consider the relationship between drift velocity and electric current.
Problems & Exercises
- A large water main is 2.50 m in diameter, and the average water velocity is 6.00 m/s. Find the Hall voltage produced if the pipe runs perpendicular to the Earth's [latex]5.00\times10^{-5}\,\text{T}[/latex] magnetic field.
- What Hall voltage is produced by a [latex]0.200\,\text{T}[/latex] magnetic field applied across a 2.60-cm-diameter aorta when blood velocity is 60.0 cm/s?
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- What is the speed of a supersonic aircraft with a 17.0-m wingspan if it experiences a 1.60-V Hall voltage between its wingtips while flying level over the Earth's north magnetic pole, where the magnetic field strength is [latex]8.00\times10^{-5}\,\text{T}[/latex]?
- Explain why very little current flows as a result of this Hall voltage.
- A nonmechanical water meter could use the Hall effect by applying a magnetic field across a metal pipe and measuring the Hall voltage produced. What is the average fluid velocity in a 3.00-cm-diameter pipe if a [latex]0.500\,\text{T}[/latex] magnetic field produces a Hall voltage of 60.0 mV?
- Calculate the Hall voltage induced across a patient's heart while being scanned by an MRI unit. Approximate the conducting path on the heart wall as a wire 7.50 cm long moving at 10.0 cm/s perpendicular to a 1.50-T magnetic field.
- A Hall probe is calibrated to produce an output of [latex]1.00\,\mu\text{V}[/latex] in a 2.00-T magnetic field. What output voltage will it produce when placed in a 0.150-T magnetic field?
- Using the information from the resistivity table presented earlier in this textbook, determine the Hall voltage produced when a 2.00-T magnetic field is applied across a 10-gauge copper wire (diameter 2.588 mm) carrying a current of 20.0 A.
- Show that, for wires made of the same material carrying the same current and placed in the same magnetic field, the Hall voltage is inversely proportional to the wire diameter. Hint: Consider how the drift velocity depends on the wire diameter.
- A patient with a pacemaker is accidentally scanned in an MRI system. A 10.0-cm section of pacemaker wire moves at 10.0 cm/s perpendicular to the magnetic field, inducing a Hall voltage of 20.0 mV. What is the magnetic field strength?
Glossary
- Hall effect
- The production of a voltage across a current-carrying conductor when it is placed in a magnetic field.
- Hall emf
- The voltage (electromotive force) generated across a current-carrying conductor by the Hall effect. When the magnetic field, charge velocity, and conductor width are mutually perpendicular, its magnitude is given by [latex]\epsilon = Blv[/latex].
The production of a voltage across a current-carrying conductor when it is placed in a magnetic field.
The voltage (electromotive force) generated across a current-carrying conductor by the Hall effect. When the magnetic field, charge velocity, and conductor width are mutually perpendicular, its magnitude is given by [latex]\epsilon = Blv[/latex].