Electromagnetic Induction, AC Circuits, and Electrical Technologies
55 RL Circuits
Learning Objectives
- Calculate the current in an RL circuit after a specified number of characteristic time constants.
- Calculate the characteristic time constant of an RL circuit.
- Sketch and interpret the current-versus-time graph for an RL circuit during switching.
Current Growth and Decay in RL Circuits
In the previous section, we learned that an inductor resists changes in the current flowing through it. Unlike a resistor, which responds immediately to an applied voltage, an inductor cannot allow the current to change instantaneously. Any attempt to increase or decrease the current changes the magnetic field around the inductor, and that changing magnetic field induces an emf that opposes the change, as described by Lenz's law.
This raises an important question: How long does this opposition last? Although the current cannot change instantly, it does eventually reach its final value after the circuit is switched on, and it eventually falls to zero after the circuit is switched off. Understanding how quickly these changes occur is important in many technologies, from electric motors and MRI gradient coils to power supplies and electronic timing circuits.
Figure 55.1 shows a simple resistor-inductor (RL) circuit used to study how current changes with time. In position 1, the battery, resistor, and inductor are connected in series so that current begins to increase. In position 2, the battery is disconnected, allowing the energy stored in the inductor's magnetic field to dissipate through the resistor.

Current Growth When an RL Circuit Is Switched On
Suppose the switch is moved to position 1 at time [latex]t=0[/latex]. Initially, no current flows through the circuit because the inductor strongly opposes any sudden increase in current. As the current slowly increases, the induced emf becomes smaller because the rate of change of current decreases. Eventually, the induced emf becomes nearly zero, and the current reaches its steady-state value
where [latex]V[/latex] is the battery voltage and [latex]R[/latex] is the total resistance of the circuit.
The current does not increase linearly. Instead, it follows an exponential growth given by
This equation has the same mathematical form as the charging of a capacitor in an RC circuit, although the underlying physics is different. In an RL circuit, the delay arises because energy must first build up in the magnetic field surrounding the inductor.
The quantity
is called the characteristic time constant of the RL circuit. Since
the time constant has units of seconds.
The time constant determines how rapidly the current approaches its final value. After one time constant,
meaning the current has reached approximately 63.2% of its final value. After another time constant, it gains 63.2% of the remaining difference. Because the process is exponential, the current never reaches the final value mathematically, but after about five time constants it is more than 99% of the final current, which is sufficiently close for nearly all practical applications.
Figure 55.1(b) illustrates this gradual increase.
The RL Time Constant
The characteristic time constant depends only on the inductance and resistance of the circuit:
- A larger inductance produces a larger time constant because the inductor stores more magnetic energy and offers greater opposition to changes in current.
- A smaller resistance also produces a larger time constant because the final current is larger, requiring more energy to be stored in the magnetic field before the steady state is reached.
Consequently, circuits containing large inductors or small resistances respond more slowly when they are switched on or off.
This behavior is important in many biomedical technologies. For example, MRI systems use large electromagnets with very high inductance. Their currents cannot be changed instantaneously because enormous amounts of magnetic energy must first be stored or removed. Electronic control systems therefore carefully regulate how quickly these currents change to protect both the equipment and the patient.
Current Decay When an RL Circuit Is Switched Off
Now suppose the switch is moved to position 2, disconnecting the battery. Although the external voltage source has been removed, the current does not immediately drop to zero. The magnetic field surrounding the inductor stores energy, and as that magnetic field collapses it induces an emf that drives current in the same direction as before, opposing the decrease in current.
The stored magnetic energy,
is gradually converted into thermal energy in the resistor. Because the rate of energy dissipation depends on [latex]I^2R[/latex], the current decreases rapidly at first and then more slowly as it approaches zero.
The current during this discharge process is described by another exponential equation:
where the same time constant
determines how quickly the current decreases.
After one time constant, the current has fallen to
or approximately 36.8% of its original value. During each additional time constant, the current falls to 36.8% of its previous value. As shown in Figure 55.1(c), the current approaches zero asymptotically and becomes negligibly small after only a few time constants.
This gradual decay explains why devices containing large inductors, such as industrial electromagnets, MRI systems, and electric motors, often continue carrying current briefly after power has been removed. The energy stored in their magnetic fields cannot disappear instantaneously and must instead be released over time.
Example 55.1: Calculating the Time Constant and Current in an RL Circuit
A circuit contains a 7.50 mH inductor connected in series with a 3.00 Ω resistor.
- Calculate the characteristic time constant of the circuit.
- If the current is initially 10.0 A, determine the current 5.00 ms after the battery is disconnected.
Strategy for (a)
The characteristic time constant of an RL circuit is determined from
Since the inductance and resistance are given, we simply substitute the known values.
Solution for (a)
Discussion for (a)
A time constant of 2.50 ms means that the current changes very rapidly but not instantaneously. After one time constant, the current has completed about 63% of its rise (or 63% of its decay). After approximately five time constants (about 12.5 ms), the current is already within 1% of its final value, and after ten time constants it is essentially indistinguishable from the steady-state value.
Strategy for (b)
After the battery is disconnected, the current decreases exponentially according to
Since the elapsed time is 5.00 ms, which is exactly two time constants, we can either substitute directly into the exponential equation or follow the current decay step by step.
Solution for (b)
After the first time constant (2.50 ms), the current decreases to 36.8% of its initial value:
After another time constant (a total of 5.00 ms), the current again falls to 36.8% of its previous value:
Alternatively, using the exponential equation directly gives
which agrees with the step-by-step calculation.
Discussion for (b)
Even after the battery has been disconnected for 5.00 ms, a current of 1.35 A is still flowing because the energy stored in the magnetic field continues to drive charge through the circuit. The current decreases exponentially rather than dropping abruptly. For example, after another 5.00 ms (four time constants total), the current would have fallen to approximately 0.183 A.
This gradual decay is important in many practical applications. In medical imaging systems such as MRI scanners, the large inductors used to generate magnetic fields cannot be switched on or off instantaneously because of the energy stored in their magnetic fields. Electronic control systems carefully manage these current changes to ensure both accurate performance and safe operation.
Current and Voltage in RL Circuits
In summary, whenever the voltage applied to an inductor changes, the current cannot respond immediately. Instead, the current changes gradually because the inductor generates an induced emf that opposes any change in current. In other words, the current lags behind the applied voltage in an RL circuit.
In the next section, we will see how this behavior influences circuits powered by alternating current (AC), where the voltage changes continuously with time. The concepts of inductive and capacitive reactance build directly on the ideas introduced here.
Section Summary
- An RL circuit consists of a resistor and an inductor connected in series. Because an inductor opposes changes in current, the current cannot increase or decrease instantaneously when the circuit is switched.
- When an RL circuit is connected to a DC voltage source, the current increases according to
[latex]I=I_0\left(1-e^{-t/\tau}\right),[/latex]
where the steady-state current is
[latex]I_0=\frac{V}{R}.[/latex] - The characteristic time constant of an RL circuit is
[latex]\tau=\frac{L}{R},[/latex]
where [latex]L[/latex] is the inductance and [latex]R[/latex] is the total circuit resistance. A larger inductance or a smaller resistance produces a slower response.
- After one time constant, the current has reached approximately 63.2% of its final value. During each additional time constant, it gains 63.2% of the remaining difference, approaching the steady-state current exponentially.
- When the voltage source is removed and the inductor discharges through the resistor, the current decreases according to
[latex]I=I_0e^{-t/\tau},[/latex]
where [latex]I_0[/latex] is the initial current at the moment the circuit is switched off.
- After one time constant, the current has fallen to approximately 36.8% of its initial value. After several time constants, the current becomes negligibly small, although it never reaches zero instantaneously.
- The gradual rise and decay of current in RL circuits are important in many technologies, including MRI systems, electromagnets, electric motors, and medical electronic equipment, where controlling the rate of change of current is essential for safe and reliable operation.
Problems & Exercises
- If you want an RL circuit to have a characteristic time constant of 1.00 s and the circuit contains a [latex]500\ \Omega[/latex] resistor, what self-inductance is required?
- An RL circuit has a characteristic time constant of 20.0 ns and a resistance of [latex]5.00\ \text{M}\Omega[/latex].
- What is the inductance of the circuit?
- What resistance would produce a time constant of 1.00 ns with the same inductance? Such a short response time might be needed in a high-speed electronic instrument such as an oscilloscope.
- A large superconducting magnet used in magnetic resonance imaging has an inductance of 50.0 H. If the current must be adjustable with a characteristic time constant of 1.00 s, what minimum resistance is required in the system?
- Verify that the current in the situation described in Example 55.1 is 0.183 A after 10.0 ms.
- Suppose you have inductors ranging from 1.00 nH to 10.0 H and resistors ranging from [latex]0.100\ \Omega[/latex] to [latex]1.00\ \text{M}\Omega[/latex]. What range of RL time constants can be produced by connecting one resistor in series with one inductor?
- A 25.0 mH inductor has an internal resistance of [latex]4.00\ \Omega[/latex].
- What is its characteristic time constant?
- If it is connected to a 12.0 V battery, what current flows after 12.5 ms?
- What percentage of the final current [latex]I_0[/latex] flows through an inductor [latex]L[/latex] in series with a resistor [latex]R[/latex] three time constants after the circuit is connected to a voltage source?
- A current of 5.00 A flows through a 1.50 H inductor and is then dissipated through a [latex]2.00\ \Omega[/latex] resistor in a circuit like the one shown in Figure 55.1, with the switch in position 2.
- What is the initial energy stored in the inductor?
- How long does it take for the current to decrease to 5.00% of its initial value?
- Calculate the average power dissipated during this interval and compare it with the initial power dissipated by the resistor.
- An 80.0 mH inductor is connected in series with a [latex]15.0\ \Omega[/latex] resistor.
- Using the exact exponential equation, determine the time required for the current to reach 99.0% of its final value, starting from zero.
- Compare your answer with an approximate estimate based on a whole number of time constants.
- Discuss whether the difference between the exact and approximate results is significant.
- A 2.00 H inductor is connected in series with a [latex]0.500\ \Omega[/latex] resistor.
- Using the exact exponential equation, determine the time required for the current to decrease to 0.100% of its initial value.
- Compare your answer with an approximate estimate based on a whole number of time constants.
- Discuss whether the difference between the exact and approximate results is significant.
Glossary
- characteristic time constant
- The characteristic time, denoted by [latex]\tau[/latex], that describes how quickly current increases or decreases in an RL circuit. It is given by
[latex]\tau=\frac{L}{R}[/latex],
where [latex]L[/latex] is the inductance and [latex]R[/latex] is the resistance. After one time constant, the current has reached about 63.2% of its final value when increasing, or decreased to about 36.8% of its initial value when decreasing.
The characteristic time, denoted by [latex]\tau[/latex], that describes how quickly current increases or decreases in an RL circuit. It is given by
[latex]\tau=\frac{L}{R}[/latex],
where [latex]L[/latex] is the inductance and [latex]R[/latex] is the resistance. After one time constant, the current has reached about 63.2% of its final value when increasing, or decreased to about 36.8% of its initial value when decreasing.