Geometric Optics, Vision and Optical Instruments

72 Physics of the Eye

Learning Objectives

  • Explain how the human eye forms images.
  • Describe why peripheral vision has lower resolution and reduced color sensitivity than central vision.
  • Define the refractive index and explain its role in vision.
  • Explain how the eye accommodates to focus on both distant and nearby objects.

The human eye is one of the most remarkable optical instruments found in nature. It continuously forms sharp images of objects over an enormous range of distances while allowing us to perceive fine detail, color, motion, and depth. Although many people require glasses or contact lenses to achieve ideal vision, the basic operation of the eye can be understood using the same principles of geometric optics developed in the previous chapters.

In this chapter we will examine how the eye forms images, why vision changes with age, and how the eye's optical properties are used in medicine and vision correction. Understanding the physics of the eye also provides the foundation for understanding cameras, microscopes, telescopes, and many modern medical imaging instruments.

Cross-sectional diagram of the human eye showing the cornea, iris, aqueous humor, ciliary fibers, lens, vitreous humor, retina, fovea, optic disc, sclera, and optic nerve.
Figure 72.1: The cornea and crystalline lens work together to focus light onto the retina, producing a real image. The fovea contains the highest density of photoreceptors and provides the sharpest vision, while the optic disc forms the natural blind spot where the optic nerve exits the eye. (Credit: OpenStax.)

Figure 72.1 illustrates the basic anatomy of the eye. The cornea and the crystalline lens together behave much like a single converging lens. Their job is to focus incoming light so that a sharp real image forms on the retina, the light-sensitive layer lining the back of the eye.

The retina contains millions of specialized photoreceptor cells that convert light into electrical signals. These signals are processed by retinal neurons before traveling through the optic nerve to the brain, where they are interpreted as the images we perceive.

The central portion of the retina, called the fovea, provides our highest visual acuity because it contains the greatest concentration of cone photoreceptors. This is why we naturally move our eyes so that objects of interest fall on the fovea. In contrast, the peripheral retina contains fewer cones and more rod photoreceptors, making it much better at detecting motion and dim light but less effective at distinguishing fine detail and color.

Clinical Connection: Why We Don't See Equally Well Everywhere

When you read a page, recognize a face, or examine a microscope slide, you are using the fovea. Peripheral vision is excellent for detecting movement and helping you navigate your surroundings, but it cannot resolve fine details. This difference reflects the unequal distribution of rods and cones across the retina.

The eye is also remarkably adaptable to changes in brightness. The pupil, whose diameter is controlled by muscles in the iris, regulates the amount of light entering the eye. Together with biochemical changes inside the photoreceptors, this allows the visual system to function over an enormous range of light intensities—from dim starlight to bright sunlight.

Another important property governing image formation is the refractive index of the tissues through which light passes. Whenever light enters a material with a different refractive index, its speed changes and the light bends according to Snell's law.

Refractive Indices of the Eye

Table 72.1 lists the refractive indices of the major optical media in the eye. Notice that the largest change occurs when light passes from air into the cornea. Consequently, the cornea supplies most of the eye's focusing power, while the crystalline lens provides the fine adjustments needed to focus objects at different distances.

Table 72.1 Refractive Indices of the Eye
Material Index of Refraction
Air 1.00
Water 1.33
Cornea 1.38
Aqueous humor 1.34
Lens 1.41 (average; highest near the center)
Vitreous humor 1.34
Ray diagram showing light entering the eye from the top and bottom of an object. The rays bend primarily at the cornea and lens before converging to form an inverted real image on the retina.
Figure 72.2: Light entering the eye bends primarily at the cornea and then again at the crystalline lens before forming a real, inverted image on the retina. The brain interprets these signals so that we perceive the world as upright.

Although light passes through several transparent structures—including the cornea, aqueous humor, lens, and vitreous humor—the optical system can usually be modeled as a single thin converging lens. As shown in Figure 72.2, rays from each point on an object converge to corresponding points on the retina, producing a real, inverted image. The visual cortex in the brain processes this information so that objects appear upright.

Accommodation

For clear vision, the image must always form precisely on the retina. Because the distance from the lens to the retina remains essentially constant, the eye changes its focal length rather than changing the image distance. This process is called accommodation.

When viewing distant objects, incoming light rays are nearly parallel and require relatively little bending. The ciliary muscles relax, causing the lens to become flatter and reducing its optical power. When viewing nearby objects, the rays reaching the eye diverge more strongly, so the ciliary muscles contract and the lens becomes thicker and more curved, increasing its focusing power.

Comparison of the eye viewing a distant object and a nearby object. The lens is flatter for distant vision and thicker for near vision, while the image forms on the retina in both cases.
Figure 72.3: Accommodation of the eye. (a) During distant vision the lens is relatively flat and the eye is relaxed. (b) During near vision the ciliary muscles increase the curvature of the lens, allowing the image to remain focused on the retina.

A healthy young adult can typically focus on objects from about [latex]25~\text{cm}[/latex] away to essentially infinity. The closest distance at which an object can be focused sharply is called the near point. As we age, the lens gradually stiffens, making accommodation increasingly difficult.

Modeling the Eye as a Thin Lens

Because the eye behaves approximately like a thin converging lens, we can analyze it using the same equations introduced earlier. Since the optical power of a lens is

[latex]P=\frac{1}{f},[/latex]

the thin-lens equation becomes

[latex]P=\frac{1}{d_o}+\frac{1}{d_i}.[/latex]

The magnification is

[latex]\frac{h_i}{h_o}=-\frac{d_i}{d_o}=m.[/latex]

For clear vision, the image distance [latex]d_i[/latex] must equal the distance from the eye's lens to the retina. Throughout this chapter, we will assume that a person with normal vision can focus on objects located between approximately [latex]25~\text{cm}[/latex] and infinity.

Example 72.1: Size of Image on Retina

What is the size of the image on the retina of a [latex]1\text{.}\text{20}×{\text{10}}^{-2}[/latex] cm diameter human hair, held at arm’s length (60.0 cm) away? Take the lens-to-retina distance to be 2.00 cm.

Strategy

We want to find the height of the image [latex]{h}_{i}[/latex], given the height of the object is [latex]{h}_{o}=1\text{.}\text{20}×{\text{10}}^{-2}[/latex] cm. We also know that the object is 60.0 cm away, so that [latex]{d}_{o}=60.0 cm[/latex]. For clear vision, the image distance must equal the lens-to-retina distance, and so [latex]{d}_{\text{i}}=2.00 cm[/latex] . The equation [latex]\frac{{h}_{\text{i}}}{{h}_{\text{o}}}=-\frac{{d}_{\text{i}}}{{d}_{\text{o}}}=m[/latex] can be used to find [latex]{h}_{i}[/latex] with the known information.

Solution

The only unknown variable in the equation [latex]\frac{{h}_{\text{i}}}{{h}_{\text{o}}}=-\frac{{d}_{\text{i}}}{{d}_{\text{o}}}=m[/latex] is [latex]{h}_{\text{i}}[/latex]:

[latex]\frac{{h}_{\text{i}}}{{h}_{\text{o}}}=-\frac{{d}_{\text{i}}}{{d}_{\text{o}}}.[/latex]

Rearranging to isolate [latex]{h}_{\text{i}}[/latex] yields

[latex]{h}_{\text{i}}=-{h}_{\text{o}}\cdot \frac{{d}_{\text{i}}}{{d}_{\text{o}}}.[/latex]

Substituting the known values gives

[latex]\begin{array}{lll}{h}_{\text{i}}& =& -\left(1.20×{\text{10}}^{-2}\phantom{\rule{0.25em}{0ex}}\text{cm}\right)\frac{2.00 cm}{\text{60.0 cm}}\\ & =& -4.00×{\text{10}}^{-4}\phantom{\rule{0.25em}{0ex}}\text{cm}.\end{array}[/latex]

Discussion

This truly small image is not the smallest discernible—that is, the limit to visual acuity is even smaller than this. Limitations on visual acuity have to do with the wave properties of light and will be discussed in the next chapter. Some limitation is also due to the inherent anatomy of the eye and processing that occurs in our brain.

Example 72.2: The Eye's Range of Optical Power

Assume the distance from the eye's lens to the retina is [latex]2.00~\text{cm}[/latex], a typical value for an adult eye. Calculate the optical power of the eye when viewing objects at the two extremes of normal vision:

  • a distant object (effectively at infinity), and
  • an object at the normal near point of [latex]25.0~\text{cm}[/latex].

Strategy

For a clear image, the retina must lie at the image position, so the image distance is fixed:

[latex]d_i=2.00~\text{cm}=0.0200~\text{m}.[/latex]

We use the power form of the thin lens equation:

[latex]P=\frac{1}{d_o}+\frac{1}{d_i},[/latex]

where distances are expressed in meters and the resulting power is in diopters ([latex]\text{D}=\text{m}^{-1}[/latex]).

Solution

Step 1: Distant vision

For an object at a very large distance,

[latex]d_o\approx\infty.[/latex]

Therefore,

[latex]P= \frac{1}{\infty} + \frac{1}{0.0200~\text{m}}.[/latex]

Since

[latex]\frac{1}{\infty}=0,[/latex]

the optical power is

[latex]P=50.0~\text{D}.[/latex]

This is the minimum power of a relaxed eye focused on distant objects.

Step 2: Near vision

For an object at the normal near point,

[latex]d_o=0.250~\text{m}.[/latex]

The required optical power is

[latex]P= \frac{1}{0.250~\text{m}} + \frac{1}{0.0200~\text{m}} = 4.00~\text{D} + 50.0~\text{D} = 54.0~\text{D}.[/latex]

Discussion

For a typical eye, the optical power increases from [latex]50.0~\text{D}[/latex] during relaxed distance vision to [latex]54.0~\text{D}[/latex] during fully accommodated near vision. This represents an increase of approximately 8% in optical power.

The increase occurs because the ciliary muscles contract, allowing the crystalline lens to become thicker and more strongly curved. The additional curvature increases the refractive power needed to focus nearby objects on the retina.

Young eyes can accommodate over a much larger range than older eyes. As people age, the crystalline lens gradually becomes stiffer and less flexible, reducing its ability to change shape. This age-related loss of accommodation is known as presbyopia. People with presbyopia typically require reading glasses or multifocal lenses that add positive optical power for near tasks.

Clinical Connection: Reading Glasses

Reading glasses are converging lenses with positive optical power, commonly ranging from about [latex]+1.00~\text{D}[/latex] to [latex]+3.50~\text{D}[/latex]. They reduce the amount of accommodation required from the eye, allowing nearby objects to be focused comfortably on the retina.

Section Summary

  • The cornea and crystalline lens work together to form a real, inverted image on the retina.
  • Image formation by the eye can be modeled using the thin lens equations:
    [latex]P=\frac{1}{d_o}+\frac{1}{d_i}[/latex]
    [latex]\frac{h_i}{h_o} = -\frac{d_i}{d_o} = m.[/latex]
  • The retina remains at a nearly fixed distance from the lens, so the eye changes its focal length by altering the shape of the crystalline lens.
  • The process of changing the eye's optical power to focus on objects at different distances is called accommodation.
  • During distance vision, the eye is relaxed and has its minimum optical power. During near vision, the lens becomes thicker, increasing the eye's optical power.
  • With age, the crystalline lens loses flexibility, reducing the eye's ability to accommodate. This condition, known as presbyopia, is commonly corrected using reading glasses or other converging lenses.

Conceptual Questions

  1. If the natural lens of a person's eye is removed during cataract surgery (as was commonly done before modern artificial intraocular lenses were available), why would eyeglasses with a power of approximately [latex]+16~\text{D}[/latex] be needed?
  2. A cataract causes the lens of the eye to become cloudy. Does this cloudiness primarily cause dispersion or diffusion (scattering) of light? Explain.
  3. During laser surgery to repair a retinal tear, the laser beam enters a relaxed eye as nearly parallel rays. Why is it important that the incoming rays be parallel?
  4. How does the optical power of a contact lens change when it is placed on the tear film covering the cornea compared with when it is measured in air? Explain your reasoning.
  5. Why is vision usually blurry when you open your eyes underwater without goggles? How do swimming goggles or a face mask restore clear vision?

Problems & Exercises

Unless otherwise stated, assume the distance from the eye's lens to the retina is [latex]2.00~\text{cm}[/latex].

  1. What is the optical power of the eye when viewing an object located [latex]50.0~\text{cm}[/latex] away?
  2. Calculate the optical power of the eye when viewing an object located [latex]3.00~\text{m}[/latex] away.
  3. In many printed books, the average letter height is approximately [latex]3.50~\text{mm}[/latex].
    1. What is the height of the image formed on the retina when the book is held [latex]30.0~\text{cm}[/latex] from the eye?
    2. Compare the image size with the dimensions of rods and cones in the fovea. What does this suggest about the level of detail that can be distinguished in printed text? (Remember that the visual system also relies on neural processing in addition to the optics of the eye.)
  4. A person's visual acuity allows them to distinguish images on the retina that are at least [latex]4.00~\mu\text{m}[/latex] high. What is the greatest distance from which this person could read letters [latex]75.0~\text{cm}[/latex] tall painted on the side of an airplane?
  5. People who perform detailed work at very close distances, such as jewelers or watchmakers, may have a near point much closer than the typical [latex]25.0~\text{cm}[/latex].
    A woman can focus clearly on an object only [latex]8.00~\text{cm}[/latex] from her eye.

    1. What is the optical power of her eye when viewing an object at this distance?
    2. What is the height of the retinal image of a [latex]1.00~\text{mm}[/latex] object, such as lettering engraved inside a ring?
    3. What would the image height be if the same object were held at the normal near-point distance of [latex]25.0~\text{cm}[/latex]?

Glossary

accommodation
the process by which the eye changes the shape of its lens to adjust its focal length and keep objects at different distances in sharp focus on the retina
fovea
the small central region of the retina with the highest density of cone photoreceptors, providing the sharpest color vision and greatest visual acuity
presbyopia
the age-related loss of the eye's ability to accommodate, making it increasingly difficult to focus on nearby objects
retina
the light-sensitive layer at the back of the eye where a real image is formed and converted into nerve signals that are sent to the brain
definition

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Introductory Physics for the Health and Life Sciences II Copyright © 2012 by OSCRiceUniversity is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.