Geometric Optics, Vision and Optical Instruments

70 Image Formation by Mirrors

Learning Objectives

  • Explain how flat mirrors form virtual images.
  • Use ray diagrams to describe image formation by spherical mirrors.
  • Calculate focal length and magnification from the radius of curvature and the object and image distances.

Mirrors are among the most familiar optical devices in everyday life. Every morning you probably look into a bathroom mirror, and many healthcare professionals rely on specialized mirrors during examinations and procedures. Dentists use small concave mirrors to enlarge teeth, physicians use mirrors in head-mounted examination lights to focus illumination, and large convex mirrors improve visibility in hospitals, laboratories, and parking facilities by providing a wider field of view.

Like lenses, mirrors redirect light to produce images. Depending on their shape, mirrors can create images that are the same size as an object, magnified, reduced, upright, or inverted. In this section, we apply the law of reflection to understand how mirrors form images and show that many of the mathematical relationships for mirrors closely parallel those developed for thin lenses.

Figure 70.1 illustrates image formation by a flat mirror. Rays of light leaving the top of the bottle reflect from the mirror and enter the observer's eye. Although the reflected rays travel only in front of the mirror, the brain naturally assumes that light travels in straight lines. When the reflected rays are extended backward, they appear to originate from a point behind the mirror. This apparent point is where the image is perceived.

Applying the law of reflection, which states that the angle of incidence equals the angle of reflection, shows that the image forms the same distance behind the mirror as the object is in front of it. Because no light actually passes through the image location, the image cannot be projected onto a screen. Such an image is called a virtual image.

Virtual images are extremely useful even though they do not physically exist at their apparent location. The image you see in a bathroom mirror, a rearview mirror, or a dressing mirror is always virtual. Your eyes receive reflected light exactly as if it originated behind the mirror, allowing your brain to reconstruct a realistic three-dimensional image.

Light rays from a bottle reflect from a flat mirror into an observer's eye. Extending the reflected rays backward locates a virtual image behind the mirror at the same distance as the object is in front.
Figure 70.1: A flat mirror forms a virtual image located the same distance behind the mirror as the object is in front. The reflected rays only appear to originate from the image location, which is why the image cannot be projected onto a screen.

Flat mirrors are only one type of mirror used in science and medicine. Curved mirrors can either concentrate light or spread it apart, depending on their shape. To understand how this happens, we first examine the focal length of a spherical mirror.

Consider the concave spherical mirrors shown in Figure 70.2. Every incoming ray obeys the law of reflection, but the exact location where the reflected rays meet depends on the mirror's shape. If the mirror is large compared with its radius of curvature (Figure 70.2(a)), rays striking different parts of the surface do not converge at exactly the same point. This optical imperfection, known as spherical aberration, produces a blurred focus.

An ideal parabolic mirror would bring all parallel rays to a single focal point regardless of where they strike the surface. However, parabolic mirrors are much more difficult and expensive to manufacture than spherical mirrors. Fortunately, when only the central portion of a spherical mirror is used (Figure 70.2(b)), spherical aberration becomes very small, and the mirror behaves almost like a perfect focusing mirror. This approximation is analogous to the thin lens approximation introduced in the previous chapter.

For a concave mirror, parallel rays reflecting from the surface converge at a point called the focal point, labeled F in Figure 70.2. The distance from the mirror's center (its vertex) to this point is the focal length, [latex]f[/latex]. Because concave mirrors bring light rays together, they are called converging mirrors, and their focal length is defined as positive.

Comparison of a large concave spherical mirror, where reflected parallel rays do not meet at a single focal point, and a smaller concave spherical mirror, where reflected parallel rays converge at focal point F. The focal length f is measured from the mirror to the focal point.
Figure 70.2: (a) A large spherical mirror does not bring all parallel rays to exactly the same point because of spherical aberration. (b) When the mirror is small compared with its radius of curvature, reflected parallel rays converge at a common focal point. The distance from the mirror to the focal point is the focal length, [latex]f[/latex]. Since a concave mirror converges light, its focal length is positive.

Just as with lenses, mirrors can be described by their optical power. A mirror that brings light to a focus over a shorter distance is considered more powerful than one with a longer focal length. Consequently, the power of a spherical mirror is also defined as

[latex]P=\frac{1}{f}[/latex]

Thus, mirrors with smaller focal lengths have larger optical powers. Highly curved mirrors concentrate light more strongly than gently curved mirrors, making them useful in applications ranging from reflecting telescopes to medical examination mirrors.

For spherical mirrors, the focal length is directly related to the mirror's radius of curvature. Using the law of reflection together with simple geometry, it can be shown that

[latex]f=\frac{R}{2}[/latex]

where [latex]R[/latex] is the radius of curvature of the mirror. A mirror with a smaller radius of curvature has a shorter focal length and therefore greater optical power.

Convex mirrors behave differently from concave mirrors. As illustrated in Figure 70.3, parallel rays reflecting from a convex mirror spread apart after reflection. When these reflected rays are extended backward, they appear to originate from a point behind the mirror known as the focal point. Because convex mirrors cause light rays to diverge, they are called diverging mirrors, and both their focal length and optical power are defined to be negative.

Parallel rays strike a convex spherical mirror and reflect outward. The reflected rays appear to originate from a focal point F located behind the mirror, indicating a negative focal length.
Figure 70.3: Parallel rays reflected from a convex spherical mirror diverge after reflection. Their backward extensions intersect at the focal point behind the mirror. Because convex mirrors diverge light, they have a negative focal length.

Ray tracing provides a simple graphical method for locating images formed by mirrors, just as it does for lenses. The following rules summarize the behavior of light rays reflecting from thin spherical mirrors.

Rules for Ray Tracing with Spherical Mirrors

  1. A ray approaching a concave (converging) mirror parallel to the principal axis reflects through the focal point on the same side of the mirror.
  2. A ray approaching a convex (diverging) mirror parallel to the principal axis reflects as though it originated from the focal point behind the mirror.
  3. A ray striking the center (vertex) of a spherical mirror obeys the law of reflection, making equal angles with the principal axis before and after reflection.
  4. A ray directed through the focal point of a concave mirror reflects parallel to the principal axis.
  5. A ray directed toward the focal point behind a convex mirror reflects parallel to the principal axis.

Because we assume the mirrors are small compared with their radii of curvature, the same mathematical relationships developed for thin lenses also apply to spherical mirrors. As a result, the mirror equation and magnification equation have exactly the same form as the thin-lens equations, differing only in the sign conventions used for mirrors.

Consider the concave mirror shown in Figure 70.4. The object is located farther from the mirror than its focal length, so [latex]d_o>f[/latex]. This configuration is directly analogous to the first case studied for converging lenses. Using the ray-tracing rules, rays originating from the same point on the object reflect and meet at a common point in front of the mirror. Since the rays physically converge, the image can be projected onto a screen and is therefore a real image.

Like the corresponding image formed by a converging lens, this image is inverted and has a positive image distance. Consequently, its magnification is negative. This situation is known as a Case 1 mirror image. The only significant difference from the lens case is that both the object and the image lie on the same side of the reflecting surface.

Ray diagram showing image formation by a concave mirror. Three rays reflected from the mirror converge to form an inverted real image in front of the mirror. The object distance, image distance, focal length, and image and object heights are labeled.
Figure 70.4: A Case 1 image formed by a concave mirror. The object is located farther from the mirror than its focal length. Three principal rays are shown: one parallel to the principal axis, one striking the center of the mirror, and one passing through the focal point before reflection. The reflected rays converge to form an inverted real image. In practice, only two rays are needed to locate the image.

Example 70.1: Locating the Heating Element in a Concave Reflector

Many electric space heaters use a concave mirror to direct infrared (IR) radiation from a heated filament toward the room. Because infrared light obeys the same law of reflection as visible light, the same mirror equations apply. Suppose the mirror has a radius of curvature of 50.0 cm and forms a real image of the heating element 3.00 m in front of the mirror. Where must the heating element be located?

Strategy

We are given the image distance, [latex]d_i=3.00\text{ m}[/latex], and the mirror's radius of curvature, [latex]R=50.0\text{ cm}[/latex]. Since the mirror is concave, its focal length is positive and equals half the radius of curvature:

[latex]f=\frac{R}{2}=\frac{50.0\text{ cm}}{2}=25.0\text{ cm}=0.250\text{ m}[/latex]

Using the mirror equation, we can determine the object distance [latex]d_o[/latex].

Solution

Start with the mirror equation:

[latex]\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}[/latex]

Rearrange to solve for the object distance:

[latex]\frac{1}{d_o}=\frac{1}{f}-\frac{1}{d_i}[/latex]

Substitute the known values:

[latex]\frac{1}{d_o}=\frac{1}{0.250\text{ m}}-\frac{1}{3.00\text{ m}}=4.00-0.333=3.667\text{ m}^{-1}[/latex]

Finally, invert the result:

[latex]d_o=\frac{1}{3.667}=0.273\text{ m}=27.3\text{ cm}[/latex]

Discussion

The heating element is located 27.3 cm from the mirror, which is slightly farther than the focal length of 25.0 cm. This is exactly the condition for a Case 1 image, in which a concave mirror produces a real image.

In this example, the reflected infrared radiation is concentrated about 3.00 m in front of the heater. In many practical heating devices this is not desirable because it creates a hot spot at a specific location. Instead, designers often place the heating element at the mirror's focal point. When the object is located at the focal point, the reflected rays emerge nearly parallel, spreading the heat more uniformly across a room.

This behavior is closely related to that of a slide projector or spotlight. As an object moves closer to the focal point, the image forms farther and farther away. When the object is placed exactly at the focal point, the image is effectively formed at infinity, and the reflected rays become parallel.

Example 70.2: Concentrating Solar Energy with a Curved Mirror

A parabolic trough is a solar-energy device that uses a curved reflecting surface to concentrate sunlight onto a dark pipe containing a fluid. The heated fluid can then transfer energy to a heat exchanger, where it may be used to produce steam and generate electricity. Figure 70.5 shows a large solar-thermal installation that uses this principle.

For this simplified model, assume that the reflector is one-quarter of a cylindrical surface and that the fluid-carrying pipe lies along its focal line. Determine the following:

  1. If the pipe is placed [latex]40.0~\text{cm}[/latex] from the mirror at its focal point, what is the mirror’s radius of curvature?
  2. How much solar power is concentrated onto each meter of pipe if the incident solar intensity is [latex]0.900~\text{kW/m}^2[/latex]?
  3. If the pipe has a diameter of [latex]2.00~\text{cm}[/latex], what is the ideal temperature increase of the mineral oil in one meter of pipe during [latex]1.00~\text{min}[/latex]? Assume that all the solar energy incident on the reflector is transferred to the oil.

Strategy

This example combines several areas of physics:

  • Part (a) uses the relationship between the focal length and radius of curvature of a concave mirror.
  • Part (b) uses geometry and the definition of intensity as power per unit area.
  • Part (c) uses density, thermal energy, and specific heat capacity.

Solution for (a)

For a spherical mirror, the focal length is related to the radius of curvature by

[latex]f=\frac{R}{2}[/latex]

Solving for [latex]R[/latex] gives

[latex]R=2f=2(40.0~\text{cm})=80.0~\text{cm}[/latex]

Solution for (b)

The incident solar intensity is

[latex]I=0.900~\text{kW/m}^2=900~\text{W/m}^2[/latex]

The reflector is modeled as one-quarter of a cylindrical surface. For a reflector length [latex]L[/latex], its area is

[latex]A=\frac{1}{4}(2\pi R)L[/latex]

For a length of [latex]1.00~\text{m}[/latex] and radius [latex]R=0.800~\text{m}[/latex],

[latex]A = \frac{\pi}{2}(0.800~\text{m})(1.00~\text{m}) = 1.26~\text{m}^2[/latex]

The solar power intercepted by this section of reflector is

[latex]P=IA = (900~\text{W/m}^2)(1.26~\text{m}^2) = 1.13\times10^3~\text{W}[/latex]

Thus, approximately [latex]1.13~\text{kW}[/latex] of solar power is concentrated onto each meter of pipe.

Solution for (c)

The thermal energy absorbed during [latex]60.0~\text{s}[/latex] is

[latex]Q=Pt = (1.13\times10^3~\text{W})(60.0~\text{s}) = 6.78\times10^4~\text{J}[/latex]

The volume of oil in one meter of pipe is

[latex]V = \pi\left(\frac{d}{2}\right)^2L = \pi(0.0100~\text{m})^2(1.00~\text{m}) = 3.14\times10^{-4}~\text{m}^3[/latex]

Using a mineral-oil density of [latex]\rho=8.00\times10^2~\text{kg/m}^3[/latex], the mass is

[latex]m = \rho V = (8.00\times10^2~\text{kg/m}^3) (3.14\times10^{-4}~\text{m}^3) = 0.251~\text{kg}[/latex]

The temperature increase is found from

[latex]Q=mc\Delta T[/latex]

Solving for [latex]\Delta T[/latex] and using [latex]c=1670~\text{J/(kg}\cdot^\circ\text{C)}[/latex],

[latex]\Delta T = \frac{Q}{mc} = \frac{6.78\times10^4~\text{J}} {(0.251~\text{kg})(1670~\text{J/(kg}\cdot^\circ\text{C)})} = 162^\circ\ \text{C}[/latex]

Discussion

In this idealized calculation, the oil temperature rises by [latex]162^\circ\ \text{C}[/latex] in one minute. The result is intentionally an upper limit because it assumes that all incident solar energy is absorbed by the oil. A real system loses energy through reflection, imperfect absorption, thermal radiation, conduction, convection, and fluid flow.

This example illustrates why concentrating mirrors are useful: they collect solar energy over a large area and direct it toward a much smaller receiver. The same optical principle is used in solar furnaces, some medical illumination systems, reflecting telescopes, and other devices that require electromagnetic radiation to be concentrated at a focal point.

Rows of parabolic trough reflectors at a solar-thermal power facility. Each curved mirror concentrates sunlight onto a pipe running along its focal line.
Figure 70.5: Parabolic trough collectors concentrate sunlight onto pipes located along their focal lines. A circulating fluid absorbs the thermal energy and transports it for later use in electricity generation. (Credit: kjkolb, Wikimedia Commons.)

When an object is placed closer to a concave mirror than the mirror’s focal length, the reflected rays diverge rather than meeting in front of the mirror. However, when the reflected rays are extended backward, they appear to originate from a point behind the mirror. The image is therefore virtual and cannot be projected onto a screen.

This situation is analogous to the image formed by a converging lens when the object is inside the focal length. Since [latex]f>d_o[/latex] and the focal length is positive, the concave mirror produces an image that is upright and larger than the object. This is the principle used by makeup mirrors, shaving mirrors, and dental mirrors when they are positioned close to the face, skin, or teeth.

A ray diagram shows an object placed inside the focal length of a concave mirror. The reflected rays diverge, but their backward extensions meet behind the mirror to form an upright, enlarged virtual image. A second image shows a person viewing a magnified reflection in a makeup mirror.
Figure 70.6: (a) When an object is placed inside the focal length of a concave mirror, the reflected rays diverge but appear to originate from a point behind the mirror. The resulting image is virtual, upright, and enlarged. (b) Makeup and examination mirrors use this arrangement to produce a magnified image. (Credit: Mike Melrose, Flickr.)

Healthcare Connection: Dental and Examination Mirrors

Dentists often use concave mirrors to inspect teeth and oral tissues. When the mirror is held closer to the tooth than its focal length, it produces an enlarged, upright virtual image. The magnification makes small features such as cracks, cavities, plaque, and changes in tissue easier to observe.

The same principle is used in some dermatological and surgical examination mirrors, where magnification can improve the visibility of small surface details.

A convex mirror behaves differently. Because it causes reflected rays to spread apart, it is a diverging mirror and has a negative focal length. A convex mirror always forms the same type of image for a real object: the image is virtual, upright, and smaller than the object.

As shown in Figure 70.7, the reflected rays do not meet in front of the mirror. Their backward extensions appear to originate from a point behind the mirror, locating the virtual image. Because the image is reduced, the mirror can display a much wider field of view than a flat mirror of the same size.

A ray diagram shows an object in front of a convex mirror. The reflected rays diverge and their backward extensions meet behind the mirror, forming an upright, reduced virtual image. A second image shows the wide field of view produced by a convex security mirror.
Figure 70.7: (a) A convex mirror always forms a virtual, upright, reduced image behind the mirror. (b) Because the image is smaller, a convex mirror provides a wider field of view than a flat mirror, making it useful for security and safety applications. (Credit: Laura D’Alessandro, Flickr.)

Convex mirrors are commonly used in vehicle side mirrors, hospital corridors, parking structures, laboratories, and stores. Their wide field of view helps observers see around corners and monitor large areas. The tradeoff is that objects appear smaller and therefore seem farther away than they actually are.

Example 70.3: Measuring Corneal Curvature with a Keratometer

A keratometer measures the curvature of the cornea and is commonly used when fitting contact lenses. The instrument directs light toward the cornea and analyzes the reflected image. Because the cornea acts approximately like a convex mirror, the size of the reflected image can be used to determine its radius of curvature.

A light source is located [latex]12.0~\text{cm}[/latex] from the cornea, and the reflected image has a magnification of [latex]0.0320[/latex]. Determine the radius of curvature of the cornea.

Strategy

We are given the object distance and magnification:

[latex]d_o=12.0~\text{cm}, \qquad m=0.0320[/latex]

We first use the magnification equation to find the image distance. We then use the mirror equation to determine the focal length. Finally, we use the relationship between focal length and radius of curvature:

[latex]R=2|f|[/latex]

Solution

The magnification equation is

[latex]m=-\frac{d_i}{d_o}[/latex]

Solving for the image distance gives

[latex]d_i=-md_o[/latex]

Substituting the known values,

[latex]d_i = -(0.0320)(12.0~\text{cm}) = -0.384~\text{cm}[/latex]

The negative image distance indicates that the image is virtual and located behind the corneal surface.

Next, use the mirror equation:

[latex]\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}[/latex]

Substituting the known values,

[latex]\frac{1}{f} = \frac{1}{12.0~\text{cm}} + \frac{1}{-0.384~\text{cm}} = -2.52~\text{cm}^{-1}[/latex]

Taking the reciprocal,

[latex]f=-0.400~\text{cm}[/latex]

The radius of curvature is twice the magnitude of the focal length:

[latex]R=2|f| = 2(0.400~\text{cm}) = 0.800~\text{cm}[/latex]

Discussion

The cornea has a radius of curvature of [latex]0.800~\text{cm}[/latex], or [latex]8.00~\text{mm}[/latex]. This is a reasonable value for the front surface of the human cornea.

The focal length is negative because the cornea acts as a convex mirror for reflected light. The negative image distance is also consistent with a virtual image located behind the reflecting surface.

In an actual eye, the cornea is not a perfect sphere, and its curvature may vary across the surface. Modern keratometers and corneal topographers therefore take measurements in multiple directions. These measurements help clinicians fit contact lenses, detect irregular astigmatism, evaluate corneal disease, and plan refractive surgery.

The three main image types formed by mirrors are directly analogous to those formed by lenses:

  • A concave mirror with the object beyond the focal point forms a real, inverted image.
  • A concave mirror with the object inside the focal length forms a virtual, upright, enlarged image.
  • A convex mirror always forms a virtual, upright, reduced image.

A useful way to remember the correspondence is that concave mirrors behave like converging lenses, while convex mirrors behave like diverging lenses.

Take-Home Experiment: Exploring Concave Mirrors

Find a flashlight and identify the curved reflector behind the bulb. Next, use a second flashlight to shine light into the reflector while the first flashlight is turned off. Observe how the reflected light behaves and estimate the reflector's focal length. If available, you can also shine a flashlight into the reflector of a car headlight (with the headlight turned off) and estimate its focal length using the same method.

This activity demonstrates how concave mirrors concentrate or collimate light and illustrates the same principles used in headlights, flashlights, telescopes, and solar concentrators.

Problem-Solving Strategy for Mirrors

The same systematic approach used for thin lenses can also be applied to mirrors.

  1. Identify the optical system. Determine that the problem involves image formation by a mirror and identify whether the mirror is flat, concave, or convex.
  2. Sketch the situation. Draw the object, mirror, principal axis, focal point, and center of curvature. A ray diagram is often the quickest way to predict the type and approximate location of the image.
  3. List the known and unknown quantities. Record the object distance, focal length (or radius of curvature), image distance, magnification, or any other given values.
  4. Determine the image type. Decide whether the image is expected to be real or virtual, upright or inverted, and magnified or reduced. This helps verify the final answer.
  5. Apply the mirror equations. For quantitative problems, use
    [latex]\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}[/latex]

    and

    [latex]m=-\frac{d_i}{d_o}=\frac{h_i}{h_o}[/latex]
  6. Check your result. Confirm that the sign of the image distance and magnification agrees with the expected image type and that the answer is physically reasonable.

Section Summary

  • A flat mirror forms an image that is the same size as the object, is located the same distance behind the mirror as the object is in front of it, and is always virtual.
  • For a spherical mirror, the focal length is one-half the radius of curvature:
    [latex]f=\frac{R}{2}[/latex]
  • Concave mirrors are converging mirrors and can produce either real or virtual images depending on the object's position relative to the focal point.
  • Convex mirrors are diverging mirrors and always produce virtual, upright, and reduced images.
  • The same image and magnification equations used for thin lenses also apply to spherical mirrors when the paraxial approximation is valid.

Conceptual Questions

  1. Describe the differences between real and virtual images. How can you determine, simply by observing an image produced by a single lens or mirror, whether it is real or virtual?
  2. Can you see a virtual image? Can you photograph one? Can a virtual image be projected onto a screen using additional optical elements? Explain your reasoning.
  3. Does a real image need to be projected onto a screen in order to exist? Explain.
  4. An image is always located at which distance: the object distance [latex]d_o[/latex], the image distance [latex]d_i[/latex], or the focal length [latex]f[/latex]?
  5. Under what conditions will the image formed by a lens or mirror be located exactly at the focal point?
  6. What does a negative magnification indicate? What does it mean physically when the magnitude of the magnification is less than one?
  7. A Case 1 image always has a negative magnification. Can such an image still be larger than the object? Explain.
  8. Figure 70.8 shows a light bulb positioned between two mirrors. One mirror produces a nearly parallel beam of light, while the second mirror redirects light that would otherwise escape. Where must the filament be located relative to the focal point (or center of curvature) of each mirror?
Two concave mirrors face one another with a light bulb between them. The larger mirror produces a parallel beam, while the smaller mirror reflects escaping light back toward the larger reflector.
Figure 70.8: A pair of concave mirrors used in a headlight design. The larger reflector produces a nearly parallel beam, while the smaller mirror redirects light that would otherwise be lost, increasing the efficiency of the headlight.
  1. Design an arrangement of mirrors that allows you to see the back of your head. What is the minimum number of mirrors required?
  2. If you want to see your entire body in a flat mirror, how tall must the mirror be? Does the required mirror size depend on how far you stand from it? Support your answer with a sketch.
  3. A flat mirror can be thought of as having an infinite focal length. If so, where does it form an image? How are the image distance [latex]d_i[/latex] and object distance [latex]d_o[/latex] related?
  4. Why are convex mirrors commonly used as vehicle side mirrors and security mirrors? What is the principal disadvantage of using a convex mirror instead of a flat mirror?

Problems & Exercises

  1. What is the focal length of a makeup mirror with an optical power of [latex]+1.50~\text{D}[/latex]?
  2. Some telephoto cameras use a curved mirror rather than a lens. What radius of curvature is required for a concave mirror to replace a telephoto lens with a focal length of [latex]800~\text{mm}[/latex]?
  3. The shiny outer surface of a spoon acts approximately as a convex mirror and has a radius of curvature of [latex]3.00~\text{cm}[/latex].
    1. Calculate the focal length of the mirror.
    2. Calculate its optical power in diopters.
  4. A concave makeup mirror produces an upright image with a magnification of [latex]1.50[/latex] when a person's face is [latex]12.0~\text{cm}[/latex] from the mirror. Determine the focal length of the mirror. Clearly identify the known quantities, unknown quantity, sign conventions, and equations used.
  5. A shopper standing [latex]3.00~\text{m}[/latex] from a convex security mirror sees an image with a magnification of [latex]0.250[/latex].
    1. Where is the image located?
    2. What is the focal length of the mirror?
    3. What is the mirror's radius of curvature?

    Clearly identify the known quantities, unknown quantities, sign conventions, and equations used.

  6. An object [latex]1.50~\text{cm}[/latex] tall is held [latex]3.00~\text{cm}[/latex] from a person's cornea. The reflected image is measured to be [latex]0.167~\text{cm}[/latex] tall.
    1. What is the magnification of the image?
    2. Where is the image located?
    3. What is the radius of curvature of the convex reflecting surface formed by the cornea?

    This method is used in keratometry to estimate corneal curvature when fitting contact lenses.

  7. Ray tracing for a flat mirror shows that the virtual image is located as far behind the mirror as the object is in front of it. Therefore,
    [latex]d_i=-d_o[/latex]
    1. Use the mirror equation to determine the focal length of a flat mirror.
    2. What is the optical power of a flat mirror?
  8. Show that a flat mirror produces an image with [latex]h_i=h_o[/latex], given that the image distance and object distance have equal magnitudes and opposite signs.
  9. Use the law of reflection and an appropriate geometric construction to show that the focal length of a spherical mirror is one-half its radius of curvature:
[latex]f=\frac{R}{2}[/latex]
  1. Explain why the relationship [latex]f=R/2[/latex] is a good approximation only when the mirror's diameter is small compared with its radius of curvature.
  2. The heating element in the concave reflector considered in Example 70.1 radiates [latex]1500~\text{W}[/latex] and has an emitting area of [latex]100~\text{cm}^2[/latex]. Assume that half of the emitted power is reflected and focused by the mirror onto a person located [latex]3.00~\text{m}[/latex] away. Calculate the intensity of the infrared radiation in [latex]\text{W/m}^2[/latex] at the person's location.
  3. Construct Your Own Problem: Consider a ceiling-mounted heat-lamp fixture containing four identical [latex]250~\text{W}[/latex] lamps connected so that the remaining lamps continue operating if one filament burns out. The ceiling is [latex]3.00~\text{m}[/latex] above the floor, and each lamp has a concave reflector behind it.Construct a problem in which you determine the resistance of each filament and the radiation intensity delivered to a selected area of the floor. State all assumptions needed, including the supply voltage, reflector efficiency, illuminated area, and distribution of the reflected radiation.

Glossary

concave mirror
a curved mirror whose reflecting surface bends inward and that can converge parallel rays of light toward a focal point
converging mirror
a concave mirror that reflects rays traveling parallel to its principal axis so that they converge near a focal point in front of the mirror
convex mirror
a curved mirror whose reflecting surface bulges outward and that produces virtual, upright, reduced images
diverging mirror
a convex mirror that reflects parallel rays so that they spread apart and appear to originate from a focal point behind the mirror
flat mirror
a plane reflecting surface that forms a virtual, upright image of the same size as the object and at an equal distance behind the mirror
law of reflection
the principle stating that the angle of reflection equals the angle of incidence, with both angles measured from the normal to the surface
radius of curvature
the radius of the sphere of which a spherical mirror forms a part; for a spherical mirror, its magnitude is approximately twice the focal length
spherical aberration
an optical imperfection in which rays striking different regions of a spherical mirror do not all converge at exactly the same point
definition

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Introductory Physics for the Health and Life Sciences II Copyright © 2012 by OSCRiceUniversity is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.