Radioactivity, Nuclear Physics and its Medical Applications

120 Half-Life and Activity

Learning Objectives

  • Define half-life and explain why radioactive decay is a statistical process.
  • Describe how radioactive dating is used to determine the age of ancient biological materials and rocks.
  • Calculate the age of an object using radioactive dating and the exponential decay law.

Radioactive nuclei are unstable and spontaneously transform into more stable nuclei through radioactive decay. However, not all radioactive isotopes decay at the same rate. Some, such as radium and polonium, decay relatively quickly, while others, such as uranium-238, remain radioactive for billions of years. Because different isotopes decay at different rates, scientists use quantitative measures such as half-life and activity to describe how long radioactive materials persist and how rapidly they decay.

Half-Life

Why do scientists use the term half-life instead of simply referring to the lifetime of a radioactive nucleus? The answer lies in the random nature of radioactive decay. As shown in Figure 120.1, the number of radioactive nuclei in a sample decreases gradually over time rather than all disappearing at once. The half-life, denoted by [latex]t_{1/2}[/latex], is defined as the time required for half of the radioactive nuclei in a sample to decay. After one half-life, one-half of the original nuclei remain. After a second half-life, half of those remaining nuclei decay, leaving one-quarter of the original sample. After a third half-life, one-eighth of the original nuclei remain, and so on. For a large collection of nuclei, this predictable pattern continues over many half-lives. The amount of radioactive material steadily decreases but never reaches exactly zero. This behavior is an example of exponential decay.

Connection to Healthcare

The concept of half-life is essential in medicine. Radioactive isotopes used in medical imaging and cancer treatment are carefully selected based on their half-lives. An isotope with a very short half-life may decay before an imaging procedure can be completed, while one with a very long half-life would expose the patient to unnecessary radiation after the procedure is finished. Choosing the appropriate half-life allows physicians to obtain useful diagnostic information while minimizing radiation dose.

Although the behavior of a large sample is highly predictable, the decay of any individual nucleus is completely random. A nucleus does not "age" or become more likely to decay simply because it has existed for a long time. A more precise way to describe half-life is in terms of probability. During one half-life, every radioactive nucleus has a 50% chance of decaying and a 50% chance of surviving. If a nucleus survives one half-life, it again has a 50% chance of surviving the next half-life. Even if it survives many half-lives, its probability of decaying during the next half-life remains exactly the same. This idea is similar to repeatedly flipping a fair coin. Each flip has a 50% chance of landing heads, regardless of the outcomes of previous flips. Likewise, each radioactive nucleus behaves independently of its past history.

Graph showing the exponential decrease in the number of radioactive nuclei remaining as time passes in units of half-life.
Figure 120.1: The number of radioactive nuclei decreases exponentially with time. During each half-life, half of the remaining nuclei decay. Although individual decay events occur randomly, the behavior of a large collection of nuclei follows a predictable exponential pattern.

Half-lives span an enormous range of values, from approximately [latex]10^{-23}\text{ s}[/latex] for the most unstable nuclei to more than [latex]10^{16}\text{ y}[/latex] for the most stable radioactive isotopes—a range of nearly 46 orders of magnitude. The concept of half-life also applies to unstable subatomic particles and to excited atomic and nuclear states. The number of radioactive nuclei remaining after a time [latex]t[/latex] is described by the exponential decay equation

[latex]N=N_0e^{-\lambda t},[/latex]

where [latex]N_0[/latex] is the initial number of radioactive nuclei, [latex]N[/latex] is the number remaining after time [latex]t[/latex], [latex]e=2.71828\ldots[/latex] is the base of the natural logarithm, and [latex]\lambda[/latex] is the decay constant. A larger decay constant corresponds to a faster rate of decay and therefore a shorter half-life. The decay constant and half-life are related by

[latex]\lambda=\frac{\ln(2)}{t_{1/2}}\approx\frac{0.693}{t_{1/2}}.[/latex]

This equation shows that the decay constant is inversely proportional to the half-life: isotopes with long half-lives have small decay constants, whereas isotopes with short half-lives have large decay constants. Substituting [latex]t=t_{1/2}[/latex] into the exponential decay equation gives

[latex]N=N_0e^{-0.693}=0.500N_0,[/latex]

confirming that exactly one-half of the original nuclei remain after one half-life. When the elapsed time is an integer number of half-lives, the calculation is straightforward: simply divide the original number of nuclei by 2 for each half-life that has passed. For example, after ten half-lives,

[latex]N=\frac{N_0}{2^{10}}=\frac{N_0}{1024}.[/latex]

For times that are not whole multiples of the half-life, the exponential equation must be used.

Radioactive Dating

One of the most important applications of radioactive decay is radioactive dating, which allows scientists to determine the age of archaeological artifacts, fossils, and geological materials. The best-known technique is radiocarbon (carbon-14) dating. Carbon-14 has a half-life of 5730 years and is continuously produced in Earth's upper atmosphere when neutrons generated by cosmic rays interact with nitrogen nuclei:

[latex]{}^{14}\mathrm{N}+n\rightarrow{}^{14}\mathrm{C}+p.[/latex]

Once formed, radioactive carbon combines with oxygen to produce carbon dioxide, which mixes throughout the atmosphere. Plants absorb this carbon dioxide during photosynthesis, and animals obtain carbon by consuming plants or other animals. As a result, every living organism contains a small, nearly constant fraction of carbon-14 mixed with stable carbon isotopes. Carbon-14 accounts for approximately [latex]1.3\times10^{-12}[/latex] of all carbon atoms. Knowing the total number of carbon atoms in a sample therefore allows the initial number of carbon-14 nuclei to be estimated. When an organism dies, it no longer exchanges carbon with its environment. The carbon-14 already present continues to decay, but no new carbon-14 is incorporated into the tissue. By measuring how much carbon-14 remains and comparing it with the amount found in living organisms, scientists can determine how much time has passed since the organism died. Radiocarbon dating is most useful for biological materials between a few hundred and about 50,000 years old. Beyond this range, so little carbon-14 remains that accurate measurements become increasingly difficult. Modern radiocarbon dating also uses calibration curves to account for small historical variations in atmospheric carbon-14 concentration, improving the accuracy of age estimates. Since its development by American chemist Willard Libby (1908–1980), radiocarbon dating has revolutionized archaeology, paleontology, and environmental science. Libby received the 1960 Nobel Prize in Chemistry for this work. One of the best-known applications of radiocarbon dating involved the Shroud of Turin, a linen cloth traditionally associated with the burial of Jesus (see Figure 120.2). In 1988, small samples of the cloth were independently analyzed by three laboratories using carbon-14 dating. To minimize bias, each laboratory received several unidentified samples, only one of which came from the shroud. All three laboratories obtained consistent results showing that the cloth retained approximately 92% of the carbon-14 found in living tissue. As demonstrated in Example 120.1, this measurement corresponds to a medieval age for the fabric.

Photographs of the Shroud of Turin, including the faint image visible on the cloth and its photographic negative, which reveals the image more clearly.
Figure 120.2: The Shroud of Turin is one of the most widely known examples of radiocarbon dating. Independent carbon-14 measurements performed in 1988 showed that the linen cloth dates to the medieval period. The image visible on the cloth remains the subject of ongoing historical and scientific investigation. (Credit: Butko, Wikimedia Commons)

Example 120.1: How Old Is the Shroud of Turin?

Radiocarbon analysis showed that the amount of [latex]{}^{14}\mathrm{C}[/latex] remaining in the Shroud of Turin was 92% of that found in living tissue. Assuming the decrease in carbon-14 is due only to radioactive decay, calculate the age of the cloth.

Strategy

If 92% of the original carbon-14 remains, then

[latex]\frac{N}{N_0}=0.92.[/latex]

We can use the radioactive decay equation

[latex]N=N_0e^{-\lambda t}[/latex]

to determine the product [latex]\lambda t[/latex]. We then calculate the decay constant from the known half-life of carbon-14,

[latex]t_{1/2}=5730\ \text{y},[/latex]

and finally solve for the age of the sample.

Solution

Starting with the exponential decay equation, divide both sides by [latex]N_0[/latex]:

[latex]\frac{N}{N_0}=e^{-\lambda t}.[/latex]

Substituting the measured fraction of carbon-14 gives

[latex]0.92=e^{-\lambda t}.[/latex]

Taking the natural logarithm of both sides,

[latex]\ln(0.92)=-\lambda t.[/latex]

Evaluating the logarithm,

[latex]-0.0834=-\lambda t.[/latex]

Solving for the age gives

[latex]t=\frac{0.0834}{\lambda}.[/latex]

Next, calculate the decay constant using the half-life of carbon-14:

[latex]\lambda=\frac{0.693}{t_{1/2}} =\frac{0.693}{5730\ \text{y}}.[/latex]

Substituting this value into the previous equation yields

[latex]t=\frac{0.0834}{0.693/(5730\ \text{y})}\approx690\ \text{y}.[/latex]

Answer: The linen is approximately 690 years old relative to the time the carbon-14 measurement was made.

Discussion

The carbon-14 measurements were performed in 1988. Subtracting the calculated age gives an estimated production date near A.D. 1300. The three independent laboratories that analyzed the samples reported a weighted average age of approximately [latex]\text{A.D. }1320\pm60[/latex], in good agreement with this calculation. Radiocarbon dating always includes some uncertainty because of counting statistics, sample preparation, contamination, and natural variations in atmospheric carbon-14 over time. Modern laboratories account for these variations using calibration curves, producing more accurate calendar dates than a simple calculation based solely on radioactive decay. This example illustrates how the exponential decay law can be used to estimate the age of ancient organic materials. The calculation itself is independent of the historical or cultural significance of the object being analyzed.

Carbon-14 dating is only one example of radioactive dating. Different isotopes are used to study materials of different ages. For example, ancient rocks can be dated using the decay of [latex]{}^{238}\mathrm{U}[/latex] into [latex]{}^{206}\mathrm{Pb}[/latex]. By measuring the ratio of uranium to lead and knowing the half-life of uranium-238, scientists can estimate when the rock solidified. Because uranium-238 has a very long half-life of approximately [latex]4.5\times10^9\ \text{y}[/latex], uranium–lead dating is useful for determining the ages of Earth's oldest rocks and even meteorites. In contrast, carbon-14 dating is limited to relatively recent biological materials because its much shorter half-life causes nearly all of the carbon-14 to decay after about 50,000 years.

Activity: The Rate of Radioactive Decay

When a radioactive source is described as highly active, this means that a large number of nuclei decay in a given amount of time. The activity, represented by [latex]R[/latex], is the rate at which radioactive decays occur:

[latex]R=\frac{\Delta N}{\Delta t},[/latex]

where [latex]\Delta N[/latex] is the number of nuclei that decay during the time interval [latex]\Delta t[/latex]. Activity describes the number of decay events, not the mass of radioactive material or the amount of energy deposited in tissue. The SI unit of activity is the becquerel (Bq), named after Henri Becquerel, one of the discoverers of radioactivity. One becquerel corresponds to one radioactive decay per second:

[latex]1\ \text{Bq}=1\ \text{decay/s}.[/latex]

Because one becquerel is a very small amount of activity, medical and laboratory sources are often labeled in kilobecquerels (kBq), megabecquerels (MBq), or gigabecquerels (GBq). Another unit of activity is the curie (Ci), named in recognition of the work of Marie and Pierre Curie. It was originally based approximately on the activity of 1 g of [latex]{}^{226}\mathrm{Ra}[/latex] and is now defined exactly as

[latex]1\ \text{Ci}=3.70\times10^{10}\ \text{Bq}.[/latex]

Thus, one curie corresponds to [latex]3.70\times10^{10}[/latex] decays each second. The curie is a very large unit, so smaller quantities such as the millicurie (mCi) and microcurie ([latex]\mu\text{Ci}[/latex]) are commonly used:

[latex]1\ \text{MBq}\approx27.0\ \mu\text{Ci}.[/latex]

Connection to Healthcare

Radioactive materials used in nuclear medicine are usually prescribed and recorded by activity rather than by mass. For example, the amount of a radiopharmaceutical administered for an imaging procedure may be listed in MBq. Activity tells healthcare professionals how many nuclear transformations occur each second, which is essential for planning image quality, timing the procedure, estimating radiation exposure, and handling radioactive materials safely. Activity alone does not determine biological risk. The type and energy of the emitted radiation, the isotope’s physical and biological half-lives, the amount absorbed by tissue, and the organs in which the material accumulates must also be considered.

The activity of a sample depends primarily on two quantities:

  • the number [latex]N[/latex] of radioactive nuclei present, and
  • the half-life [latex]t_{1/2}[/latex] of the isotope.

A sample containing more radioactive nuclei generally undergoes more decays per second. For the same number of nuclei, an isotope with a shorter half-life has a greater activity because its nuclei decay more rapidly. The activity is related to the decay constant by

[latex]R=\lambda N.[/latex]

Using

[latex]\lambda=\frac{0.693}{t_{1/2}},[/latex]

we obtain

[latex]R=\frac{0.693N}{t_{1/2}}.[/latex]

This relationship shows that activity is directly proportional to the number of radioactive nuclei and inversely proportional to the isotope’s half-life. The units used for [latex]t_{1/2}[/latex] must match the desired time unit for the activity. To obtain activity in becquerels, the half-life must be expressed in seconds.

Example 120.2: Carbon-14 Activity in Living Tissue

Calculate the activity due to [latex]{}^{14}\mathrm{C}[/latex] in 1.00 kg of carbon from a living organism. Express the activity in becquerels and curies.

Strategy

We use

[latex]R=\frac{0.693N}{t_{1/2}}.[/latex]

To calculate the activity, we need the number [latex]N[/latex] of carbon-14 nuclei and the carbon-14 half-life:

[latex]t_{1/2}=5730\ \text{y}.[/latex]

We first calculate the total number of carbon atoms in 1.00 kg of carbon. We then multiply by the approximate carbon-14 abundance in living material, [latex]1.3\times10^{-12}[/latex], to obtain the number of carbon-14 nuclei.

Solution

Because the molar mass of carbon is approximately 12.0 g/mol, the number of carbon atoms in 1.00 kg is

[latex]N(\text{carbon}) = \left(\frac{1000\ \text{g}}{12.0\ \text{g/mol}}\right) \left(6.02\times10^{23}\ \text{atoms/mol}\right) = 5.02\times10^{25}.[/latex]

The number of carbon-14 nuclei is therefore

[latex]N({}^{14}\mathrm{C}) = \left(5.02\times10^{25}\right) \left(1.3\times10^{-12}\right) = 6.52\times10^{13}.[/latex]

Substituting this value into the activity equation gives

[latex]R = \frac{0.693\left(6.52\times10^{13}\right)} {5730\ \text{y}} = 7.89\times10^{9}\ \text{y}^{-1}.[/latex]

This corresponds to [latex]7.89\times10^{9}[/latex] decays per year. To convert to becquerels, convert years to seconds:

[latex]R = \left(7.89\times10^{9}\ \text{y}^{-1}\right) \left(\frac{1\ \text{y}}{3.16\times10^{7}\ \text{s}}\right) = 250\ \text{s}^{-1}.[/latex]

Therefore,

[latex]R=250\ \text{Bq}.[/latex]

To express this activity in curies, use [latex]1\ \text{Ci}=3.70\times10^{10}\ \text{Bq}[/latex]:

[latex]R = \frac{250\ \text{Bq}} {3.70\times10^{10}\ \text{Bq/Ci}} = 6.76\times10^{-9}\ \text{Ci}.[/latex]

Thus,

[latex]R=6.76\ \text{nCi}.[/latex]

Answer: The carbon-14 activity in 1.00 kg of carbon from living tissue is approximately

[latex]R=250\ \text{Bq}=6.76\ \text{nCi}.[/latex]

Discussion

This result means that approximately 250 carbon-14 nuclei decay each second in every kilogram of carbon from living tissue. At first, this may seem like a large number, but the activity is very small compared with many medical and industrial radioactive sources. For 1.00 g of carbon, the activity would be only

[latex]0.250\ \text{Bq},[/latex]

or about one decay every four seconds. Detecting such a small activity requires sensitive equipment and careful subtraction of background radiation. The measurement becomes even more difficult for ancient samples because less carbon-14 remains. Carbon-14 is only one of several naturally occurring radioactive isotopes found in the human body. Other examples include [latex]{}^{40}\mathrm{K}[/latex]. These isotopes contribute to the natural background radiation experienced by all living organisms.

Human-Made Radioactivity

Radioactive isotopes can also be produced artificially in nuclear reactors, particle accelerators, and specialized isotope-production facilities. These isotopes have many beneficial applications, including medical imaging, cancer treatment, sterilization of medical equipment, scientific research, industrial measurements, and food irradiation. In nuclear medicine, isotopes are selected according to the type of radiation they emit, their chemical behavior in the body, and their half-lives. Diagnostic isotopes should generally remain active long enough to complete an examination but decay quickly enough to limit unnecessary exposure. Therapeutic isotopes must deliver sufficient radiation to the intended tissue while minimizing damage to surrounding healthy structures. Radioactive materials must nevertheless be handled carefully. Large accidental releases can contaminate air, soil, water, and food supplies. The 1986 accident at the Chernobyl nuclear power plant released several important radionuclides, including [latex]{}^{131}\mathrm{I}[/latex], [latex]{}^{90}\mathrm{Sr}[/latex], and [latex]{}^{137}\mathrm{Cs}[/latex]. These isotopes differ greatly in half-life, chemical behavior, and biological effects. For example, radioactive iodine can accumulate in the thyroid, whereas cesium can be distributed more broadly through soft tissues. The Chernobyl accident illustrates why both activity and isotope identity matter when evaluating radioactive contamination. A numerical activity alone does not fully describe the health risk unless the type of radiation, exposure pathway, distribution in the body, and duration of exposure are also known.

Human and Medical Applications

Radioactivity has become an indispensable tool in medicine, science, and industry. Carefully controlled radioactive sources are used to diagnose disease, treat cancer, sterilize medical equipment, preserve food, and inspect manufactured components without causing damage. At the same time, radioactive materials must be handled responsibly because accidental releases can have long-lasting environmental and health consequences. As the 1986 Chernobyl accident discussed above illustrates, understanding the activity and identity of released isotopes such as [latex]{}^{137}\mathrm{Cs}[/latex] is essential for assessing environmental contamination and radiation risk.

A visitor measures radiation levels near the Chernobyl Nuclear Power Plant using a handheld radiation detector.
Figure 120.3: Radiation levels near the Chernobyl Nuclear Power Plant are still monitored decades after the 1986 accident. The event released several radioactive isotopes into the environment and demonstrated the importance of nuclear safety, radiation monitoring, and long-term environmental remediation. (Credit: Elena Filatova, Wikimedia Commons)

Example 120.3: Estimating the Mass of [latex]{}^{137}\mathrm{Cs}[/latex] Released at Chernobyl

It is estimated that the Chernobyl accident released approximately 6.0 MCi of [latex]{}^{137}\mathrm{Cs}[/latex] into the environment. Calculate the corresponding mass of cesium-137.

Strategy

We are given the activity rather than the amount of material. Therefore, we first determine the number of radioactive nuclei using

[latex]R=\frac{0.693N}{t_{1/2}},[/latex]

where the half-life of cesium-137 is

[latex]t_{1/2}=30.2\ \text{y}.[/latex]

After finding the number of nuclei, we convert that value into moles using Avogadro's number and then determine the mass.

Solution

Rearranging the activity equation gives

[latex]N=\frac{Rt_{1/2}}{0.693}.[/latex]

Substituting the given activity,

[latex]N=\frac{(6.0\ \text{MCi})(30.2\ \text{y})}{0.693}.[/latex]

Convert curies to becquerels and years to seconds before performing the calculation:

[latex]\begin{aligned} N&= \frac{ (6.0\times10^6\ \text{Ci}) (3.70\times10^{10}\ \text{Bq/Ci}) (30.2\ \text{y}) (3.16\times10^7\ \text{s/y}) } {0.693} \\ &=3.1\times10^{26}\ \text{nuclei}. \end{aligned}[/latex]

One mole of [latex]{}^{137}\mathrm{Cs}[/latex] has a mass of 137 g and contains [latex]6.02\times10^{23}[/latex] nuclei. Therefore,

[latex]\begin{aligned} m&= \left( \frac{137\ \text{g}} {6.02\times10^{23}} \right) \left( 3.1\times10^{26} \right) \\ &\approx7.0\times10^4\ \text{g}\\ &=70\ \text{kg}. \end{aligned}[/latex]

Answer: Approximately 70 kg of cesium-137 corresponded to an activity of 6.0 MCi.

Discussion

Although 70 kg is a relatively modest mass compared with the amount of fuel in a nuclear reactor, cesium-137 has a half-life of about 30 years and is therefore extremely radioactive. This example illustrates an important concept: activity depends on both the amount of radioactive material and its half-life. Even a relatively small mass can produce an enormous activity if the isotope decays rapidly. The Chernobyl accident released many radionuclides besides cesium-137. Each isotope contributed differently to environmental contamination depending on its half-life, chemical properties, and the type of radiation it emitted. Modern reactor designs incorporate multiple passive and active safety systems intended to reduce the likelihood and consequences of such accidents.

Like the number of radioactive nuclei, the activity of a radioactive source decreases exponentially with time. Since activity is proportional to the number of undecayed nuclei, it follows the same mathematical form:

[latex]R=R_0e^{-\lambda t},[/latex]

where [latex]R_0[/latex] is the activity at [latex]t=0[/latex]. As time passes, the activity decreases by one-half during each half-life. For example, a source with an initial activity of 1.00 mCi will have an activity of 0.500 mCi after one half-life, 0.250 mCi after two half-lives, and 0.125 mCi after three half-lives. For elapsed times that are not exact multiples of the half-life, the exponential decay equation must be used.

Connection to Healthcare

The exponential decrease in activity is fundamental to nuclear medicine. Radiopharmaceuticals begin to lose activity immediately after they are produced, so hospitals carefully schedule their preparation, transportation, and administration. For example, fluorine-18 used in PET imaging has a half-life of only about 110 minutes, requiring production and patient imaging to occur within a few hours. Understanding how activity changes with time allows healthcare professionals to calculate the correct dose and ensure high-quality diagnostic images while minimizing radiation exposure.

Interactive Exploration: Alpha Decay

Alpha decay is a type of radioactive decay in which an unstable nucleus emits an alpha particle. An alpha particle contains two protons and two neutrons, making it identical to the nucleus of a helium-4 atom. When alpha decay occurs, the parent nucleus loses two protons and two neutrons. Its atomic number therefore decreases by 2, and its mass number decreases by 4. Because the atomic number changes, the decay transforms the original nucleus into a different element. In this simulation, you will observe alpha particles escaping from polonium nuclei and compare the behavior of a single nucleus with that of a large collection of radioactive nuclei. Individual decay events occur randomly, but a large sample follows a predictable exponential pattern characterized by its half-life.

Figure 120.4: The Alpha Decay simulation allows you to observe the random decay of individual nuclei and the predictable behavior of a large radioactive sample.

Guided Exploration

As you work with the simulation, use the following questions to guide your observations:

  1. Observe a single polonium nucleus. Can you predict the exact moment when it will emit an alpha particle?
  2. Repeat the observation several times. Does the nucleus decay after the same amount of time in every trial?
  3. Switch to a large collection of radioactive nuclei. How does the number of undecayed nuclei change as time passes?
  4. Compare a single nucleus with a large sample. Why is the decay time of one nucleus unpredictable while the behavior of many nuclei follows a regular pattern?
  5. Observe the parent and daughter nuclei before and after alpha decay. By how much do the atomic number and mass number change?
  6. Does the daughter nucleus represent the same element as the parent nucleus? Explain using the change in atomic number.
  7. Use your observations to explain why half-life describes the statistical behavior of a large population rather than the lifetime of one particular nucleus.

After completing the exploration, compare your observations with the mathematical model developed in this chapter. A single nucleus may decay at any time, and its exact decay time cannot be predicted. In contrast, a large collection of nuclei decreases in a regular exponential pattern. After one half-life, approximately half of the original radioactive nuclei remain. Each alpha decay follows the general pattern

[latex]{}^{A}_{Z}X\rightarrow{}^{A-4}_{Z-2}Y+{}^{4}_{2}\mathrm{He},[/latex]

where [latex]X[/latex] is the parent nucleus, [latex]Y[/latex] is the daughter nucleus, and [latex]{}^{4}_{2}\mathrm{He}[/latex] is the emitted alpha particle.

Life Sciences Connection: Radiocarbon Dating in Ecology and Environmental Science

Radioactive dating is a core tool well beyond archaeology. Ecologists use carbon-14 dating on peat bogs, buried wood, and lake-bottom sediment cores to reconstruct how forests, wetlands, and climates have changed over thousands of years, since each layer of accumulated organic material preserves the carbon-14-to-carbon-12 ratio present in the atmosphere at the time it formed. In old-growth forest research, radiocarbon dating of buried logs and soil carbon helps scientists estimate how long carbon has been locked away in an ecosystem, which is important for understanding how much carbon a forest or peatland can store and how quickly that carbon might be released as CO2 if the ecosystem is disturbed. Beyond carbon-14, environmental scientists use longer-lived isotopes such as lead-210 to date recent sediment layers in lakes and estuaries, tracking pollution history, or uranium-series dating to determine the age of coral reefs and cave formations, which in turn reveals past sea levels and rainfall patterns. In every case, the same exponential decay law and half-life concept from this section is what lets a measured isotope ratio be converted into an age.

Section Summary

  • The half-life, [latex]t_{1/2}[/latex], is the time required for approximately half of the radioactive nuclei in a large sample to decay. Although the decay of an individual nucleus is random, the behavior of a large collection of nuclei follows a predictable exponential law.
  • The number of radioactive nuclei remaining after a time [latex]t[/latex] is given by
    [latex]N=N_0e^{-\lambda t},[/latex]

    where [latex]N_0[/latex] is the initial number of nuclei and [latex]\lambda[/latex] is the decay constant.

  • The decay constant and half-life are related by
    [latex]\lambda=\frac{0.693}{t_{1/2}}.[/latex]

    A short half-life corresponds to a large decay constant and therefore a faster rate of decay.

  • Radioactive dating uses the predictable decrease in radioactive nuclei to determine the ages of archaeological artifacts, biological materials, and geological samples. Different radioactive isotopes are useful for different age ranges because they have different half-lives.
  • The activity of a radioactive source is the number of decays occurring per unit time:
    [latex]R=\frac{\Delta N}{\Delta t}.[/latex]
  • The SI unit of activity is the becquerel (Bq), defined as
    [latex]1\ \text{Bq}=1\ \text{decay/s}.[/latex]

    Medical imaging and research applications commonly express activity in kBq, MBq, or GBq.

  • Another commonly used unit is the curie (Ci):
    [latex]1\ \text{Ci}=3.70\times10^{10}\ \text{Bq}.[/latex]

    The curie remains in widespread use in nuclear medicine and radiation safety, although the becquerel is the SI unit.

  • The activity of a radioactive sample depends on both the number of radioactive nuclei and the isotope's half-life:
    [latex]R=\frac{0.693N}{t_{1/2}} =\lambda N.[/latex]
  • Because activity is proportional to the number of undecayed nuclei, it also decreases exponentially with time:
    [latex]R=R_0e^{-\lambda t},[/latex]

    where [latex]R_0[/latex] is the initial activity of the source.

  • Understanding half-life and activity is essential in medicine because radioactive isotopes are selected and administered based on how quickly they decay and how much activity is required for diagnostic imaging or therapeutic treatments.

Conceptual Questions

  1. A rock is 3.0 × 109 years old and originally contained uranium-238, which has a half-life of 4.5 × 109 years. We expect some uranium-238 to remain today. Why are its decay products—such as [latex]{}^{226}\mathrm{Ra}[/latex], [latex]{}^{222}\mathrm{Rn}[/latex], and [latex]{}^{210}\mathrm{Po}[/latex]—also found in the rock even though their half-lives are much shorter (1600 years, 3.8 days, and 138 days, respectively)?
  2. Does the number of radioactive nuclei in a sample decrease to exactly one-half of its original value after one half-life? Explain your answer in terms of the statistical nature of radioactive decay.
  3. Radioactivity depends on the nucleus rather than on the atom's chemical state. Why, then, is one kilogram of pure uranium more radioactive than one kilogram of uranium hexafluoride (UF6)?
  4. A bound nucleus has less mass than the sum of its individual protons and neutrons. Explain why this mass difference occurs. Why is an analogous effect not noticeable for ordinary objects, such as a building constructed from individual bricks?
  5. Spontaneous radioactive decay occurs only when the decay products have a smaller total mass than the parent nucleus and typically produces a more stable daughter nucleus. Explain how this is related to nuclear binding energy, particularly the binding energy per nucleon.
  6. To obtain the most accurate value of the nuclear binding energy (BE) from
    [latex]\mathrm{BE} = \left[ ZM\left({}^{1}\mathrm{H}\right) + Nm_n \right]c^2 - m\left({}^{A}X\right)c^2,[/latex]

    the binding energies of the atomic electrons should also be considered. Would including these electron binding energies increase or decrease the calculated nuclear binding energy? Why is this correction usually negligible?

  7. The average binding energy per nucleon reaches its maximum for nuclei with mass numbers near [latex]A\approx60[/latex]. Explain how this observation is related to the finite range of the strong nuclear force.

Problems & Exercises

  1. Data from the periodic table and the appendices may be useful when solving these problems.
  2. An old campfire is uncovered during an archaeological excavation. The charcoal is found to contain less than one-thousandth of the normal amount of [latex]{}^{14}\mathrm{C}[/latex]. Estimate the minimum age of the charcoal. (Hint: [latex]2^{10}=1024[/latex].)
  3. A [latex]{}^{60}\mathrm{Co}[/latex] source was originally labeled as having an activity of 4.00 mCi, but its present activity is measured to be [latex]1.85\times10^7[/latex] Bq.
    1. What is the present activity in mCi?
    2. How long ago did the source actually have an activity of 4.00 mCi?
    1. Calculate the activity, in curies, of 1.00 g of [latex]{}^{226}\mathrm{Ra}[/latex].
    2. The curie was originally intended to equal the activity of exactly 1 g of radium-226. Explain why your calculated value is not exactly 1.00 Ci.
  4. Show that the activity of the [latex]{}^{14}\mathrm{C}[/latex] contained in 1.00 g of carbon from living tissue is approximately 0.250 Bq.
  5. Gas lantern mantles contain thorium because thorium oxide can withstand extremely high temperatures. Natural thorium consists almost entirely of [latex]{}^{232}\mathrm{Th}[/latex], which has a half-life of [latex]1.405\times10^{10}\ \text{y}[/latex]. If a lantern mantle contains 300 mg of thorium, what is its activity?
  6. Milk produced near nuclear reactors may be tested for as little as 1.00 pCi of [latex]{}^{131}\mathrm{I}[/latex] per liter. What mass of iodine-131 corresponds to this activity?
    1. Natural potassium contains the radioactive isotope [latex]{}^{40}\mathrm{K}[/latex], which has a half-life of [latex]1.277\times10^9\ \text{y}[/latex]. What mass of [latex]{}^{40}\mathrm{K}[/latex] in a person's body would produce an activity of 4140 Bq?
    2. If the person has 140 g of total potassium in the body (typical for a 70-kg adult), what fraction of natural potassium is [latex]{}^{40}\mathrm{K}[/latex]?
  7. A researcher isolates 1.00 mg of the relatively rare isotope [latex]{}^{235}\mathrm{U}[/latex]. If this sample has an activity of 80.0 Bq, determine the half-life of uranium-235 in years.
  8. [latex]{}^{50}\mathrm{V}[/latex] has one of the longest known radioactive half-lives. If the activity of 1.00 kg of [latex]{}^{50}\mathrm{V}[/latex] is measured to be 1.75 Bq, determine its half-life.
  9. Antique red uranium-glass vases obtain their color from small amounts of uranium. Research the naturally occurring uranium isotopes and their half-lives, then calculate the activity of a vase containing 2.00 g of uranium. Neglect the activity of daughter nuclides.
  10. A tree dies in a forest. How many years must pass before the carbon-14 activity in 1.00 g of the tree's carbon decreases to 1.00 decay per hour?
  11. What fraction of the original [latex]{}^{40}\mathrm{K}[/latex] present when Earth formed [latex]4.5\times10^9[/latex] years ago remains today?
  12. A 5000-Ci [latex]{}^{60}\mathrm{Co}[/latex] source used for cancer therapy is considered too weak for clinical use when its activity falls to 3500 Ci. How long after manufacture does this occur?
  13. Natural uranium today consists of 0.7200% [latex]{}^{235}\mathrm{U}[/latex] and 99.27% [latex]{}^{238}\mathrm{U}[/latex]. What were the percentages of these two isotopes when Earth formed approximately [latex]4.5\times10^9[/latex] years ago?
  14. The beta particles emitted by tritium ([latex]{}^{3}\mathrm{H}[/latex]) produce light in self-luminous exit signs. At manufacture, a sign contains 15.0 Ci of tritium.
    1. What is the mass of tritium?
    2. What will its activity be 5.00 years after manufacture?
  15. Many World War II aircraft instruments used radium-painted luminous dials.
    1. If the activity of one instrument was [latex]1.0\times10^5[/latex] Bq when new, what mass of [latex]{}^{226}\mathrm{Ra}[/latex] did it contain?
    2. Assuming the radium remained in the instrument, what is its activity 57.0 years later?
    1. A laboratory source of [latex]{}^{210}\mathrm{Po}[/latex] is labeled as having an activity of 1.0 μCi on the day it was prepared. A student measures the source 120 days later and records 1500 counts per minute with a Geiger counter. What fraction of the radioactive decays is detected?
    2. List several reasons why a detector records only a fraction of the emitted alpha particles.
  16. Armor-piercing ammunition sometimes contains depleted uranium, which is composed almost entirely of [latex]{}^{238}\mathrm{U}[/latex].
    1. Calculate the activity of 60.0 g of pure [latex]{}^{238}\mathrm{U}[/latex].
    2. Calculate the activity of 60.0 g of natural uranium, neglecting [latex]{}^{234}\mathrm{U}[/latex] and all daughter nuclides.
  17. A vintage red-orange Fiesta® plate contains approximately 50.0 g of [latex]{}^{238}\mathrm{U}[/latex] in its glaze.
    1. Determine its activity.
    2. Calculate the total energy released as the uranium eventually decays.
    3. If electrical energy costs $0.12 per kWh, what would be the monetary value of that energy?
  18. Suppose a 4000-kg block of depleted uranium ([latex]{}^{238}\mathrm{U}[/latex]) is used as an aircraft counterweight.
    1. Calculate its activity.
    2. How many food Calories per day are produced as the radioactive decay energy is converted into heat?
    3. Would you expect this heat to be detectable? Explain.
  19. The Galileo spacecraft, launched in 1989, was powered by 11.0 kg of [latex]{}^{238}\mathrm{Pu}[/latex]. The isotope emits 5.59-MeV alpha particles and has a half-life of 87.7 years.
    1. What was its initial activity in becquerels?
    2. What thermal power did it initially produce?
    3. What power did it produce 12.0 years after launch? Ignore contributions from daughter nuclei and escaping gamma rays.
  20. Construct Your Own Problem. Design a problem involving a radioisotope power source for a spacecraft. Specify the isotope, its half-life, decay energy, the required electrical power, and the mission duration. Then determine the amount of radioactive material required.
  21. Unreasonable Results. A physicist discovers 1.0 μg of [latex]{}^{236}\mathrm{U}[/latex] in uranium ore and assumes it has been present since Earth's formation. The isotope has a half-life of [latex]2.3\times10^7\ \text{y}[/latex].
    1. Calculate how much uranium-236 would have been required 4.5 × 109 years ago for 1.0 μg to remain today.
    2. Why is the result unreasonable?
    3. Which assumption is responsible for the unreasonable result?
  22. Unreasonable Results.
    1. Repeat Problem 15, but include the 0.0055% natural abundance of [latex]{}^{234}\mathrm{U}[/latex], whose half-life is [latex]2.45\times10^5\ \text{y}[/latex].
    2. Why is the result unreasonable?
    3. Which assumption causes the difficulty?
    4. If uranium-234 is not primordial, where does it come from?
  23. Unreasonable Results. A smoke-alarm manufacturer claims that the smallest detectable alpha-particle current is 1.00 μA.
    1. Determine the activity, in curies, of an alpha emitter that would produce this current.
    2. Why is the result unreasonable?
    3. Which simplifying assumption is responsible?

Glossary

activity
The rate at which radioactive nuclei decay, usually measured in becquerels (Bq) or curies (Ci).
becquerel (Bq)
The SI unit of radioactivity, equal to one radioactive decay per second.
carbon-14 dating
A radiometric dating technique that estimates the age of once-living materials by measuring the remaining amount of carbon-14.
curie (Ci)
A traditional unit of radioactivity equal to [latex]3.70\times10^{10}[/latex] decays per second, or [latex]3.70\times10^{10}[/latex] Bq.
decay constant ([latex]\lambda[/latex])
A constant that characterizes the probability of radioactive decay and is related to the half-life by [latex]\lambda=0.693/t_{1/2}[/latex].
half-life ([latex]t_{1/2}[/latex])
The time required for approximately one-half of the radioactive nuclei in a large sample to decay.
radioactive dating
A family of techniques that determine the age of materials by measuring the decay of radioactive isotopes.
rate of decay
The number of radioactive decay events that occur per unit time.
definition

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Introductory Physics for the Health and Life Sciences II Copyright © 2012 by OSCRiceUniversity is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.