Electric Potential and Electric Field
11 Electric Potential Energy: Potential Difference
Learning Objectives
- Define electric potential and electric potential energy.
- Describe the relationship between potential difference and electrical potential energy.
- Explain electron volt and its usage in submicroscopic processes.
- Determine electric potential energy given potential difference and amount of charge.
The ideas of electric potential, potential difference, and electric potential energy are central to understanding electricity in both technology and biology—but they are not immediately intuitive. We will build these ideas step by step using physical analogies and then connect them to real biological systems.
From Force to Energy: The Big Picture
Previously, we focused on the electric force:
This tells us how strongly an electric field pushes or pulls on a charge. But in many real systems—especially biological ones—we are less interested in the force itself and more interested in energy transfer. For example:
- How much energy is delivered in a defibrillator pulse?
- How much energy does an ion gain when it crosses a membrane?
- How much energy is required to move a charge inside a cell?
These questions are energy questions, not force questions.
When a charge moves in an electric field, the field does work on it. For a conservative force (like gravity or electrostatics),
If the electric field does positive work on a charge, the charge’s electric potential energy decreases. The “lost” potential energy appears as kinetic energy.
Analogy: Gravitational Potential Energy
Consider a ball at the top of a hill. It has gravitational potential energy because of its position. When it rolls downhill:
- Gravitational potential energy decreases.
- Kinetic energy increases.
The height determines how much energy per unit mass is available. Similarly, in electricity:
- Electric potential energy depends on position in an electric field.
- Charge moving “downhill” in electric potential loses potential energy and gains kinetic energy.
The electric field is like the slope of the hill.
Electric Potential Energy (PE)
Electric potential energy (PE) is the energy a charge has because of its position in an electric field. It is measured in joules (J).
If a charge moves from point A to point B, the change in electric potential energy is:
If the electric field accelerates a positive charge, then:
- The field does positive work.
- The charge speeds up.
- Its potential energy decreases.
This is exactly analogous to gravity.
Electric Potential (Voltage)
Because electric potential energy depends on the amount of charge, we define a new quantity that removes this dependence:
Electric potential [latex]V[/latex] is energy per unit charge.
This is extremely important:
- Potential energy depends on how much charge you have.
- Electric potential (voltage) does not.
Just as gravitational potential (height) does not depend on the mass of the object, electric potential does not depend on the test charge.
Electric Potential
Unit: volt (V)
Potential Difference (Voltage Between Two Points)
In real systems we rarely care about potential at just one point. What matters is the difference in potential between two points:
By definition:
Rearranging:
This equation is one of the most important relationships in this chapter.
Potential Difference and Energy
Energy equals charge times voltage difference.
Why Voltage Is Not Energy
This is a common point of confusion.
A 12-V motorcycle battery and a 12-V car battery have the same voltage. But the car battery can deliver much more energy.
Why?
Because:
If [latex]\Delta V[/latex] is the same but the car battery can move more charge [latex]q[/latex], then it delivers more total energy.
Voltage tells you how much energy each coulomb of charge would gain—not how many coulombs are available.
Biological Example: Cell Membrane Potential
Cells maintain voltage differences across their membranes (typically around −70 mV for neurons).
If a sodium ion ([latex]\text{Na}^+[/latex]) crosses a membrane with a potential difference of 70 mV:
Since the charge of a single ion is:
The energy change is:
This energy scale is tiny in joules—but extremely significant at the molecular level.
Electron Volt (eV)
Because atomic and molecular energies are so small in joules, we use a more convenient unit: the electron volt (eV).
One electron volt is the energy gained by an electron moving through 1 volt:
Using electron volts makes microscopic processes easier to interpret:
- Chemical bond energies: a few eV
- UV photon energies: several eV
- X-rays: thousands of eV (keV)
This is directly relevant in health sciences:
- UV radiation can damage DNA because its photon energy is comparable to molecular bond energies.
- Ionizing radiation has energies high enough (many eV or keV) to remove electrons from atoms.
Example 11.1 Calculating Energy
Suppose you have a 12.0 V motorcycle battery that can move 5000 C of charge, and a 12.0 V car battery that can move 60,000 C of charge. How much energy does each deliver? (Assume that the numerical value of each charge is accurate to three significant figures.)
Strategy
To say we have a 12.0 V battery means that its terminals have a 12.0 V potential difference. When such a battery moves charge, it puts the charge through a potential difference of 12.0 V, and the charge is given a change in potential energy equal to [latex]\text{ΔPE =}\phantom{\rule{0.25em}{0ex}}q\Delta V[/latex].
So to find the energy output, we multiply the charge moved by the potential difference.
Solution
For the motorcycle battery, [latex]q=\text{5000 C}[/latex] and [latex]\Delta V=\text{12.0 V}[/latex]. The total energy delivered by the motorcycle battery is
Similarly, for the car battery, [latex]q=\text{60},\text{000}\phantom{\rule{0.25em}{0ex}}\text{C}[/latex] and
Discussion
While voltage and energy are related, they are not the same thing. The voltages of the batteries are identical, but the energy supplied by each is quite different. Note also that as a battery is discharged, some of its energy is used internally and its terminal voltage drops, such as when headlights dim because of a low car battery. The energy supplied by the battery is still calculated as in this example, but not all of the energy is available for external use.
In the previous example, we focused primarily on the magnitude of the energy involved. However, in electricity, the sign of the energy change carries important physical meaning. Understanding the sign carefully helps avoid one of the most common conceptual confusions in this topic: how negative charges behave in electric fields and how batteries actually deliver energy.
Recall the fundamental relationship between electric potential energy and potential difference:
This equation tells us that the change in electric potential energy depends on two things:
- The amount and sign of the charge [latex]q[/latex]
- The potential difference [latex]\Delta V[/latex]
Now consider a 12-V car battery connected to a headlight, as shown in Figure 11.2. The battery maintains a potential difference of +12 V between its terminals. By definition,
where B is the positive terminal and A is the negative terminal.
In metal wires, the moving charges are electrons. An electron has charge
Electrons are repelled by the negative terminal and attracted toward the positive terminal. Even though the positive terminal is at higher potential, electrons move toward it because they carry negative charge.
Substituting into [latex]\Delta \text{PE} = q \Delta V[/latex], we see:
The change in potential energy is negative. This means the battery’s stored electric potential energy decreases as electrons move through the circuit. That “lost” potential energy is converted into other forms—light and thermal energy in the headlight.

Example 11.2 How Many Electrons Move through a Headlight Each Second?
Suppose a 12.0 V battery runs a single 30.0 W headlight. How many electrons pass through the headlight each second?
Understanding the Physical Meaning
Power is the rate at which energy is transferred:
A 30.0 W headlight uses 30.0 joules every second. That means in one second, the battery loses 30.0 J of electric potential energy:
The negative sign reflects that the battery is losing energy.
Relating Energy to Charge
Using
we solve for [latex]q[/latex]:
Thus, 2.50 coulombs of charge move through the headlight each second.
Converting Charge to Number of Electrons
Each electron carries charge:
This extraordinarily large number explains why current appears smooth and continuous. Electric current in everyday circuits involves the coordinated motion of vast numbers of electrons.
The Electron Volt
The energy per electron in the previous example is extremely small in joules. At atomic and molecular scales, joules are not convenient units. For that reason, we define the electron volt (eV).
One electron volt is the energy gained by a single elementary charge accelerated through a potential difference of 1 volt:
This definition is powerful because it creates a direct numerical relationship:
- An electron accelerated through 1 V gains 1 eV.
- Through 100 V → 100 eV.
- Through 100 kV → 100 keV.
The electron volt is especially useful in biology and medicine:
- Chemical bond energies are typically a few eV.
- Ultraviolet photons carry several eV and can damage DNA.
- X-rays carry thousands of eV (keV).
- Nuclear decay energies are often in the MeV range.
For example, if breaking an organic bond requires 5 eV, then a 30 keV particle could, in principle, disrupt:
This illustrates how radiation damage occurs at the molecular level.
Conservation of Energy in Electric Fields
For conservative forces such as electrostatic forces, mechanical energy is conserved:
or
When a charged particle moves in an electric field, a decrease in electric potential energy results in an increase in kinetic energy.
Example 11.3 Electrical Potential Energy Converted to Kinetic Energy
Calculate the final speed of an electron accelerated from rest through 100 V.
Since the electron starts from rest, [latex]\text{KE}_i = 0[/latex]. All electric potential energy becomes kinetic energy:
This speed is several million meters per second—demonstrating how small voltages can significantly accelerate very light particles like electrons. At much higher voltages, relativistic effects must be considered.
Section Summary
- Electric potential is potential energy per unit charge.
- The potential difference between points A and B, [latex]{V}_{B}–{V}_{A}[/latex], defined to be the change in potential energy of a charge [latex]q[/latex] moved from A to B, is equal to the change in potential energy divided by the charge, Potential difference is commonly called voltage, represented by the symbol[latex]\text{Δ}V[/latex]. [latex]\Delta V=\frac{\text{ΔPE}}{q}\phantom{\rule{0.25em}{0ex}}\text{and ΔPE =}\phantom{\rule{0.25em}{0ex}}q\Delta V\text{.}[/latex]
- An electron volt is the energy given to a fundamental charge accelerated through a potential difference of 1 V. In equation form, [latex]\begin{array}{lll}\text{1 eV}& =& \left(1.60×{\text{10}}^{\text{–19}}\phantom{\rule{0.25em}{0ex}}\text{C}\right)\left(1 V\right)=\left(1.60×{\text{10}}^{\text{–19}}\phantom{\rule{0.25em}{0ex}}\text{C}\right)\left(1 J/C\right)\\ & =& 1.60×{\text{10}}^{\text{–19}}\phantom{\rule{0.25em}{0ex}}\text{J.}\end{array}[/latex]
- Mechanical energy is the sum of the kinetic energy and potential energy of a system, that is, [latex]\text{KE}+\text{PE}.[/latex] This sum is a constant.
Conceptual Questions
- Voltage is the common word for potential difference. Which term is more descriptive, voltage or potential difference?
- If the voltage between two points is zero, can a test charge be moved between them with zero net work being done? Can this necessarily be done without exerting a force? Explain.
- What is the relationship between voltage and energy? More precisely, what is the relationship between potential difference and electric potential energy?
- Voltages are always measured between two points. Why?
- How are units of volts and electron volts related? How do they differ?
Problems & Exercises
- Find the ratio of speeds of an electron and a negative hydrogen ion (one having an extra electron) accelerated through the same voltage, assuming non-relativistic final speeds. Take the mass of the hydrogen ion to be [latex]1\text{.}\text{67}×{\text{10}}^{–\text{27}}\phantom{\rule{0.25em}{0ex}}\text{kg}\text{.}[/latex]
- An evacuated tube uses an accelerating voltage of 40 kV to accelerate electrons to hit a copper plate and produce x rays. Non-relativistically, what would be the maximum speed of these electrons?
- A bare helium nucleus has two positive charges and a mass of [latex]6\text{.}\text{64}×{\text{10}}^{\text{–27}}\phantom{\rule{0.25em}{0ex}}\text{kg}\text{.}[/latex] (a) Calculate its kinetic energy in joules at 2.00% of the speed of light. (b) What is this in electron volts? (c) What voltage would be needed to obtain this energy?
- Integrated Concepts Singly charged gas ions are accelerated from rest through a voltage of 13.0 V. At what temperature will the average kinetic energy of gas molecules be the same as that given these ions?
- Integrated Concepts The temperature near the center of the Sun is thought to be 15 million degrees Celsius [latex]\left(1.5×{\text{10}}^{7}\phantom{\rule{0.25em}{0ex}}ºC\right)[/latex]. Through what voltage must a singly charged ion be accelerated to have the same energy as the average kinetic energy of ions at this temperature?
- Integrated Concepts (a) What is the average power output of a heart defibrillator that dissipates 400 J of energy in 10.0 ms? (b) Considering the high-power output, why doesn’t the defibrillator produce serious burns?
- Integrated Concepts A lightning bolt strikes a tree, moving 20.0 C of charge through a potential difference of [latex]1.00×{\text{10}}^{\text{2}}\phantom{\rule{0.25em}{0ex}}\text{MV}[/latex]. (a) What energy was dissipated? (b) What mass of water could be raised from [latex]\text{15ºC}[/latex] to the boiling point and then boiled by this energy? (c) Discuss the damage that could be caused to the tree by the expansion of the boiling steam.
- Integrated Concepts A 12.0 V battery-operated bottle warmer heats 50.0 g of glass, [latex]2.50×{\text{10}}^{\text{2}}\phantom{\rule{0.25em}{0ex}}\text{g}[/latex] of baby formula, and [latex]2.00×{\text{10}}^{\text{2}}\phantom{\rule{0.25em}{0ex}}\text{g}[/latex] of aluminum from [latex]\text{20}\text{.}0ºC[/latex] to [latex]90.0ºC[/latex]. (a) How much charge is moved by the battery? (b) How many electrons per second flow if it takes 5.00 min to warm the formula? (Hint: Assume that the specific heat of baby formula is about the same as the specific heat of water.)
- Integrated Concepts A battery-operated car utilizes a 12.0 V system. Find the charge the batteries must be able to move in order to accelerate the 750 kg car from rest to 25.0 m/s, make it climb a [latex]2.00×{\text{10}}^{\text{2}}\phantom{\rule{0.25em}{0ex}}\text{m}[/latex] high hill, and then cause it to travel at a constant 25.0 m/s by exerting a [latex]5.00×{\text{10}}^{\text{2}}\phantom{\rule{0.25em}{0ex}}\text{N}[/latex] force for an hour.
- Integrated Concepts Fusion probability is greatly enhanced when appropriate nuclei are brought close together, but mutual Coulomb repulsion must be overcome. This can be done using the kinetic energy of high-temperature gas ions or by accelerating the nuclei toward one another. (a) Calculate the potential energy of two singly charged nuclei separated by [latex]1\text{.}\text{00}×{\text{10}}^{\text{–12}}\phantom{\rule{0.25em}{0ex}}\text{m}[/latex] by finding the voltage of one at that distance and multiplying by the charge of the other. (b) At what temperature will atoms of a gas have an average kinetic energy equal to this needed electrical potential energy?
- Unreasonable Results (a) Find the voltage near a 10.0 cm diameter metal sphere that has 8.00 C of excess positive charge on it. (b) What is unreasonable about this result? (c) Which assumptions are responsible?
- Construct Your Own Problem Consider a battery used to supply energy to a cellular phone. Construct a problem in which you determine the energy that must be supplied by the battery, and then calculate the amount of charge it must be able to move in order to supply this energy. Among the things to be considered are the energy needs and battery voltage. You may need to look ahead to interpret manufacturer’s battery ratings in ampere-hours as energy in joules.
Glossary
- electric potential
- potential energy per unit charge
- potential difference (or voltage)
- change in potential energy of a charge moved from one point to another, divided by the charge; units of potential difference are joules per coulomb, known as volt
- electron volt
- the energy given to a fundamental charge accelerated through a potential difference of one volt
- mechanical energy
- sum of the kinetic energy and potential energy of a system; this sum is a constant