Electric Current, Resistance, and Ohm’s Law

19 Current

Learning Objectives

  • Define electric current, ampere, and drift velocity.
  • Describe the direction of charge flow in conventional current.
  • Use drift velocity to calculate current and vice versa.

Electric Current

Electric current is defined as the rate at which electric charge flows. A large current—such as the current used to start a truck engine—moves a large amount of charge in a short time. A small current—such as the one used to operate a handheld calculator—moves a smaller amount of charge over a longer time. In equation form, electric current
[latex]I[/latex] is defined by:

[latex]I=\frac{\Delta Q}{\Delta t}[/latex]

Here, [latex]\Delta Q[/latex] is the amount of charge that passes through a given cross-sectional area during the time interval [latex]\Delta t[/latex]. (Often the initial time is taken as zero, so [latex]\Delta t=t[/latex].) See Figure 19.1.
The SI unit for current is the ampere (A), named for the French physicist André-Marie Ampère (1775–1836). Since
[latex]I=\Delta Q/\Delta t[/latex], an ampere is one coulomb per second:

[latex]\text{1 A}=\text{1 C/s}[/latex]

Current ratings appear everywhere in health and everyday technology—for example, on fuses and circuit breakers (patient-room outlets and medical devices must be protected from overload), as well as on battery packs, chargers, and many electronic instruments.

Charges are shown as small spheres moving through a section of a conducting wire. The direction of movement of charge is indicated by arrows along the length of the conductor toward the right. The cross-sectional area of the wire is labeled as A. The current is equal to the flow of charge.
Figure 19.1 The rate of flow of charge is current. An ampere is the flow of one coulomb through an area in one second.

Example 19.1: Calculating Currents: Current in a Truck Battery and a Handheld Calculator

(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine?
(b) How long does it take 1.00 C of charge to flow through a handheld calculator if a 0.300-mA current is flowing?

Strategy

We use the definition of current, [latex]I=\Delta Q/\Delta t[/latex]. In part (a), charge and time are given. In part (b), we rearrange the definition to solve for time.

Solution for (a)

Substitute the given values into the definition of current:

[latex]\begin{aligned} I&=\frac{\Delta Q}{\Delta t} =\frac{720~\text{C}}{4.00~\text{s}} =180~\text{C/s} =180~\text{A}. \end{aligned}[/latex]

Discussion for (a)

This large current reflects the fact that a large amount of charge is moved in a short time. Starter motors draw large currents because significant forces must be overcome to set an engine in motion.

Solution for (b)

Solve [latex]I=\Delta Q/\Delta t[/latex] for time:

[latex]\begin{aligned} \Delta t&=\frac{\Delta Q}{I} =\frac{1.00~\text{C}}{0.300\times10^{-3}~\text{C/s}} =3.33\times10^{3}~\text{s}. \end{aligned}[/latex]

Discussion for (b)

This is slightly less than an hour. A handheld calculator uses a very small current, so it takes a long time to move even 1 C of charge. Calculators still “turn on” instantly because they require very little energy overall, and their components do not need large mechanical motion like an engine.

Figure 19.2 shows a simple circuit and its schematic representation: a battery, conducting path, and a load (shown as a resistor). Schematics help us focus on the essential features of a circuit. The same schematic in Figure 19.2(b) could represent many systems—from a truck headlight to a small penlight—because the physics of current and energy transfer is analyzed in the same way.

Part a shows a bulb glowing when its terminals are connected to a battery through a wire. The voltage of the battery is labeled as V. The current through the bulb is represented as I, and the current direction is shown using arrows emerging from the positive terminal of the battery, passing through the bulb, and entering the negative terminal of the battery. Part b shows an electric circuit diagram with a resistance connected across the terminals of a battery of voltage V. The current is shown using arrows as emerging from the positive terminal of the battery, passing through the resistance, and entering the negative terminal of the battery.
Figure 19.2 (a) A simple electric circuit. A closed conducting path allows current to flow through a load connected to a battery. (b) A schematic representation of the same idea: the battery is drawn as parallel lines, wires as straight lines, and the zigzag is the load. The same schematic can represent many different real-world circuits.

Notice that the current direction shown in Figure 19.2 is from positive to negative. By definition,
conventional current points in the direction that positive charge would flow.
Depending on the material, the moving charges may be positive, negative, or both. In metal wires, current is carried mainly by electrons (negative charges). In ionic solutions—such as salt water or the fluid inside and outside cells—both positive and negative ions can move, and this is directly relevant to nerve and muscle signaling.

It is also important to recognize that an electric field exists inside a conductor carrying current (see Figure 19.3). Unlike a conductor in electrostatic equilibrium (where the internal electric field is zero), a conductor with current is not in static equilibrium. The electric field provides the push that transfers energy to the charge carriers.

Making Connections: Take-Home Investigation—Electric Current Illustration

Find a straw and small peas (or beads) that can move freely through it. Place the straw flat on a table and fill it with peas. When you push one pea in at one end, a different pea should pop out the other end. This is an analogy for electric current.
Identify what corresponds to the electrons (or ions) and what corresponds to the supply of energy. What other analogies can you think of for electric current?

Note: the peas move by bumping into one another, while charges in a conductor respond to electric forces (repulsion among like charges and forces from the electric field).

In part a, positive charges move toward the right through a conducting wire. The direction of movement of charge is indicated by arrows along the length of the wire. The area of a cross section of the wire is labeled as A. The direction of the electric field E is toward the right, in the same direction as movement of positive charge. The current direction is also toward the right, shown by an arrow. In part b, negative charges move toward the left through a conducting wire. The direction of movement of charge is indicated by arrows along the length of the wire. The area of a cross section of the wire is labeled as A. The direction of the electric field E is toward the right, opposite the direction of movement of negative charge. The current direction is also toward the right, shown by an arrow.
Figure 19.3 Current [latex]I[/latex] is the rate at which charge moves through an area [latex]A[/latex] (the wire’s cross-section). Conventional current is defined to point in the direction of the electric field. (a) Positive charges move with the electric field, so their motion matches conventional current. (b) Electrons (negative charges) drift opposite the electric field, but conventional current still points with the field. The direction of electron motion is sometimes called electronic flow.

Example 19.2: Calculating the Number of Electrons that Move through a Calculator

If the 0.300-mA current through the calculator mentioned in Example 19.1 is carried by electrons, how many electrons per second pass through it?

Strategy

Conventional current is defined in the direction of positive charge flow, but electrons carry negative charge. The magnitude of the electron current is the same as the conventional current, but with opposite sign:
[latex]{I}_{\text{electrons}}=-0.300\times10^{-3}~\text{C/s}[/latex].
Since each electron has charge [latex]-1.60\times10^{-19}~\text{C}[/latex], we can convert coulombs per second into electrons per second.

Solution

Start from the definition of current for electrons:

[latex]{I}_{\text{electrons}}=\frac{\Delta Q_{\text{electrons}}}{\Delta t}=-0.300\times10^{-3}~\frac{\text{C}}{\text{s}}[/latex]

Divide by the charge per electron to find electrons per second:

[latex]\begin{aligned} \frac{e^-}{\text{s}} &=\left(-0.300\times10^{-3}~\frac{\text{C}}{\text{s}}\right)\left(\frac{1~e^-}{-1.60\times10^{-19}~\text{C}}\right)\\ &=1.88\times10^{15}~\frac{e^-}{\text{s}}. \end{aligned}[/latex]

Discussion

Even very small currents involve enormous numbers of charge carriers each second. Individual electrons are not noticed, just as individual water molecules are not noticed in water flow. Also, electrons do not march straight through a wire; they undergo frequent collisions and random motion, but with a small net “drift” that produces the current.

Drift Velocity

Electrical signals appear to move extremely quickly. A phone call carried by electrical signals can travel long distances with no noticeable delay, and a light turns on as soon as a switch is flipped. In many circuits, the signal (a change in electric field and charge distribution) propagates at speeds on the order of
[latex]10^{8}~\text{m/s}[/latex], a significant fraction of the speed of light.
Surprisingly, the individual charge carriers that make up the current move much more slowly on average, typically with drift speeds around
[latex]10^{-4}~\text{m/s}[/latex].

The rapid signal speed occurs because electric forces act quickly across the conductor. When a charge is pushed into a wire, it repels nearby charges, which repel charges farther down the line. Because charge density in a conductor cannot increase easily, an incoming charge effectively “forces” another charge to leave the far end almost immediately (see Figure 19.4). More precisely, the quickly moving “shock wave” is a rapidly propagating change in the electric field throughout the conductor.

Negatively charged electrons move through a conducting wire. Two electrons are shown entering the wire from one end, and two electrons are shown leaving the wire at the other end. The direction of movement of charge is indicated by arrows along the length of the wire toward the right. Some electrons are shown inside the wire.
Figure 19.4 When charged particles are forced into a conductor, an equal number are quickly forced to leave. Repulsion between like charges makes it difficult to increase charge density, so the electrical signal is transmitted rapidly forward.

Good conductors contain large numbers of mobile charge carriers. In metals, these carriers are free electrons. Figure 19.5 shows that individual electrons undergo many collisions with atoms and other electrons, so their motion is largely random—similar to the random motion of gas molecules. However, an electric field exists inside the wire, and it creates a small net motion superimposed on this random motion. The drift velocity [latex]v_{\text{d}}[/latex] is the average velocity of the charge carriers (for electrons, the drift is opposite the electric field).

The diagram shows a section of a conducting wire. A free electron is shown in the wire, and the path of the electron is shown as zigzag arrows along the length of the wire. The path is shown beginning at one end of the wire and ending at the other end. The drift velocity, v sub d, is indicated by an arrow toward the right, opposite the direction of the electric field E and the current I.
Figure 19.5 Free electrons in a conductor undergo frequent collisions, so their path is zigzag and mostly random. The average velocity of the free charges is the drift velocity, [latex]v_{\text{d}}[/latex]. For electrons, drift is opposite the electric field. Collisions transfer energy to the conductor, so a steady current requires a continuous energy supply.

Conduction of Electricity and Heat

Materials that are good electrical conductors are often good thermal conductors as well. A large number of mobile electrons can carry both electric charge (current) and thermal energy.

Collisions of free electrons with the lattice atoms transfer energy to the material. The electric field does work on the charges, but in a steady current that work does not build up as increasing electron speed; instead, the work is transferred to the conductor as thermal energy, often raising its temperature. That is why a continual power input is required to maintain current in ordinary conductors.
An important exception is a superconductor, which can sustain current with essentially no energy loss.

Making Connections: Take-Home Investigation—Filament Observations

Find a lightbulb with a visible filament. Look carefully at the filament and describe its structure. To what points is the filament connected?

We can relate drift velocity to current by counting the charge carriers in a segment of wire, as shown in Figure 19.6. Let [latex]n[/latex] be the number of free charges per unit volume (the carrier density). A shaded segment of wire with cross-sectional area [latex]A[/latex] and length [latex]x[/latex] has volume [latex]Ax[/latex], so it contains [latex]nAx[/latex] carriers. If each carrier has charge [latex]q[/latex], then the charge in that segment is [latex]\Delta Q = qnAx[/latex]. If all of that charge moves out of the segment in time [latex]\Delta t[/latex], then:

[latex]I=\frac{\Delta Q}{\Delta t}=\frac{qnAx}{\Delta t}[/latex]

Since the carriers move an average distance [latex]x[/latex] in time [latex]\Delta t[/latex], the magnitude of the drift velocity is
[latex]v_{\text{d}} = x/\Delta t[/latex]. Substituting [latex]x/\Delta t=v_{\text{d}}[/latex] gives:

[latex]I=nqAv_{\text{d}}[/latex]

In this expression, [latex]I[/latex] is the current through a wire of cross-sectional area [latex]A[/latex]. The material has carrier density [latex]n[/latex], each carrier has charge [latex]q[/latex], and the carriers drift with average speed [latex]v_{\text{d}}[/latex]. This relationship is useful in both directions: given a current, it can predict drift velocity; given drift velocity, it can predict current.

Charges are shown moving through a section of a conducting wire. The charges have a drift velocity v sub d along the length of the wire, shown by an arrow pointing to the right. The volume of a segment of the wire is equal to A times x, where x equals the product of the drift velocity, v sub d, and time t. A cross section of the wire is marked as A, and the length of the section is x.
Figure 19.6 All the charges in the shaded volume of the wire move out in time [latex]t[/latex], with drift speed [latex]v_{\text{d}}=x/t[/latex].

Drift velocity is only part of the story. Individual electrons move much faster than [latex]v_{\text{d}}[/latex] due to their random thermal motion; the drift velocity is the small net average caused by the electric field. Also, not every electron in a metal is free to move throughout the material. In a metal lattice, some electrons are loosely bound and can move through a “sea” of electrons shared by the atoms. These are the free electrons that respond to an applied electric field, collide with the lattice, and transfer energy to the material as heat. In an insulator, electrons are more tightly bound and cannot move freely, so current is much smaller.

Example 19.3: Calculating Drift Velocity in a Common Wire

Calculate the drift velocity of electrons in a 12-gauge copper wire (diameter 2.053 mm) carrying a 20.0-A current, assuming there is one free electron per copper atom. The density of copper is
[latex]8.80\times10^{3}~\text{kg/m}^3[/latex].

Strategy

Use [latex]I=nqAv_{\text{d}}[/latex]. The current [latex]I=20.0~\text{A}[/latex] and the electron charge is
[latex]q=-1.60\times10^{-19}~\text{C}[/latex]. Compute the cross-sectional area using [latex]A=\pi r^2[/latex], with
[latex]r=(2.053~\text{mm})/2[/latex]. Determine [latex]n[/latex] (electrons per cubic meter) from copper’s density, its molar mass (63.54 g/mol), and Avogadro’s number,
[latex]6.02\times10^{23}~\text{atoms/mol}[/latex].

Solution

First find the free-electron density [latex]n[/latex]. One free electron per atom means [latex]n[/latex] equals the number of copper atoms per cubic meter:

[latex]\begin{aligned} n &=\left(\frac{1~e^-}{\text{atom}}\right) \left(\frac{6.02\times10^{23}~\text{atoms}}{\text{mol}}\right) \left(\frac{1~\text{mol}}{63.54~\text{g}}\right) \left(\frac{1000~\text{g}}{1~\text{kg}}\right) \left(\frac{8.80\times10^{3}~\text{kg}}{1~\text{m}^3}\right)\\ &=8.342\times10^{28}~\frac{e^-}{\text{m}^3}. \end{aligned}[/latex]

Next compute the wire’s cross-sectional area:

[latex]\begin{aligned} A&=\pi r^2 =\pi\left(\frac{2.053\times10^{-3}~\text{m}}{2}\right)^2 =3.310\times10^{-6}~\text{m}^2. \end{aligned}[/latex]

Solve [latex]I=nqAv_{\text{d}}[/latex] for drift velocity:

[latex]\begin{aligned} v_{\text{d}} &=\frac{I}{nqA}\\ &=\frac{20.0~\text{A}}{\left(8.342\times10^{28}~\text{m}^{-3}\right)\left(-1.60\times10^{-19}~\text{C}\right)\left(3.310\times10^{-6}~\text{m}^2\right)}\\ &=-4.53\times10^{-4}~\text{m/s}. \end{aligned}[/latex]

Discussion

The negative sign indicates that electrons drift opposite the direction of conventional current. The magnitude is on the order of
[latex]10^{-4}~\text{m/s}[/latex], which is extremely slow compared with the speed at which electrical signals propagate through the circuit (often near
[latex]10^{8}~\text{m/s}[/latex]).

Section Summary

  • Electric current [latex]I[/latex] is the rate at which charge flows:
    [latex]I=\frac{\Delta Q}{\Delta t}[/latex]

    where [latex]\Delta Q[/latex] is the amount of charge passing through an area in time [latex]\Delta t[/latex].

  • The direction of conventional current is defined as the direction positive charge would move.
  • The SI unit for current is the ampere (A), where
    [latex]\text{1 A}=\text{1 C/s}[/latex]
  • Current can be carried by free charges, such as electrons in metals and ions in biological fluids.
  • Drift velocity [latex]v_{\text{d}}[/latex] is the average velocity of these charge carriers.
  • Current is proportional to drift velocity:
    [latex]I=nqAv_{\text{d}}[/latex]

    where [latex]n[/latex] is the carrier density, [latex]q[/latex] is the charge per carrier, and [latex]A[/latex] is the wire’s cross-sectional area.

  • Electrical signals can propagate through circuits at speeds about [latex]10^{12}[/latex] times larger than typical electron drift speeds.

Conceptual Questions

  1. Can a wire carry a current and still be neutral—that is, have a total charge of zero? Explain.
  2. Car batteries are rated in ampere-hours ([latex]\text{A}\cdot \text{h}[/latex]). To what physical quantity do ampere-hours correspond (voltage, charge, . . .), and what relationship do ampere-hours have to energy content?
  3. If two different wires having identical cross-sectional areas carry the same current, will the drift velocity be higher or lower in the better conductor? Explain in terms of the equation [latex]{v}_{\text{d}}=\frac{I}{\text{nqA}}[/latex], by considering how the density of charge carriers [latex]n[/latex] relates to whether or not a material is a good conductor.
  4. Why are two conducting paths from a voltage source to an electrical device needed to operate the device?
  5. In cars, one battery terminal is connected to the metal body. How does this allow a single wire to supply current to electrical devices rather than two wires?
  6. Why isn’t a bird sitting on a high-voltage power line electrocuted? Contrast this with the situation in which a large bird hits two wires simultaneously with its wings.

Problems & Exercises

  1. What is the current in milliamperes produced by the solar cells of a pocket calculator through which 4.00 C of charge passes in 4.00 h?
  2. A total of 600 C of charge passes through a flashlight in 0.500 h. What is the average current?
  3. What is the current when a typical static charge of [latex]0\text{.}\text{250}\phantom{\rule{0.25em}{0ex}}\mu \text{C}[/latex] moves from your finger to a metal doorknob in [latex]1.00\phantom{\rule{0.25em}{0ex}}\mu \text{s}[/latex]?
  4. Find the current when 2.00 nC jumps between your comb and hair over a [latex]0\text{.}\text{500 -}\phantom{\rule{0.25em}{0ex}}\mu \text{s}[/latex] time interval.
  5. A large lightning bolt had a 20,000-A current and moved 30.0 C of charge. What was its duration?
  6. The 200-A current through a spark plug moves 0.300 mC of charge. How long does the spark last?
  7. (a) A defibrillator sends a 6.00-A current through the chest of a patient by applying a 10,000-V potential as in the figure below. What is the resistance of the path? (b) The defibrillator paddles make contact with the patient through a conducting gel that greatly reduces the path resistance. Discuss the difficulties that would ensue if a larger voltage were used to produce the same current through the patient, but with the path having perhaps 50 times the resistance. (Hint: The current must be about the same, so a higher voltage would imply greater power. Use this equation for power: [latex]P={I}^{2}R[/latex].)
    Figure represents a defibrillation unit used on a patient. The circuit is also represented. It shows a capacitor driving a current through the chest of a patient. The opposite plates of the capacitor are marked as positive Q and negative Q. The direction of current in the connecting wires from the capacitor to the defibrillation unit is shown in a clockwise direction with an arrow on the wire, and the direction of electrons is shown opposite to this direction with an arrow.
    Figure 19.7: The capacitor in a defibrillation unit drives a current through the heart of a patient.
  8. During open-heart surgery, a defibrillator can be used to bring a patient out of cardiac arrest. The resistance of the path is [latex]5\text{00 Ω}[/latex] and a 10.0-mA current is needed. What voltage should be applied?
  9. (a) A defibrillator passes 12.0 A of current through the torso of a person for 0.0100 s. How much charge moves? (b) How many electrons pass through the wires connected to the patient? (See figure two problems earlier.)
  10. A clock battery wears out after moving 10,000 C of charge through the clock at a rate of 0.500 mA. (a) How long did the clock run? (b) How many electrons per second flowed?
  11. The batteries of a submerged non-nuclear submarine supply 1000 A at full speed ahead. How long does it take to move Avogadro’s number ([latex]6\text{.}\text{02}×{\text{10}}^{\text{23}}[/latex]) of electrons at this rate?
  12. Electron guns are used in X-ray tubes. The electrons are accelerated through a relatively large voltage and directed onto a metal target, producing X-rays. (a) How many electrons per second strike the target if the current is 0.500 mA? (b) What charge strikes the target in 0.750 s?
  13. A large cyclotron directs a beam of [latex]{\text{He}}^{\text{++}}[/latex] nuclei onto a target with a beam current of 0.250 mA. (a) How many [latex]{\text{He}}^{\text{++}}[/latex] nuclei per second is this? (b) How long does it take for 1.00 C to strike the target? (c) How long before 1.00 mol of [latex]{\text{He}}^{\text{++}}[/latex] nuclei strike the target?
  14. Repeat the above example on Example 19.3, but for a wire made of silver and given there is one free electron per silver atom.
  15. Using the results of the above example on Example 19.3, find the drift velocity in a copper wire of twice the diameter and carrying 20.0 A.
  16. A 14-gauge copper wire has a diameter of 1.628 mm. What magnitude current flows when the drift velocity is 1.00 mm/s? (See above example on Example 19.3 for useful information.)
  17. SPEAR, a storage ring about 72.0 m in diameter at the Stanford Linear Accelerator (closed in 2009), has a 20.0-A circulating beam of electrons that are moving at nearly the speed of light. (See Figure 19.8.) How many electrons are in the beam?
The circuit shows a doughnut shaped storage ring called SPEAR. The cross sections of ring are marked as A and are represented as dotted circular sections. The diameter of storage ring as measured between diametrically opposite cross sections on both ends is seventy two meters. The current in the ring is given as twenty amps. The direction of current I is shown opposite to the direction of movement of electrons e using arrows.
Figure 19.8: Electrons circulating in the storage ring called SPEAR constitute a 20.0-A current. Because they travel close to the speed of light, each electron completes many orbits in each second.

Glossary

electric current
the rate at which charge flows, I = ΔQt
ampere
(amp) the SI unit for current; 1 A = 1 C/s
drift velocity
the average velocity at which free charges flow in response to an electric field

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Introductory Physics for the Health and Life Sciences II Copyright © 2012 by OSCRiceUniversity is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.